0.6(10x+19) = 2.8(0.2x + 5)

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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The equation given is:

0.6(10x + 19) = 2.8(0.2x + 5)

This equation can be solved by expanding both sides, combining like terms, and isolating the variable x. Here's how you can approach solving it:

1. Distribute the numbers outside the parentheses:
   - Left side: 0.6 * 10x + 0.6 * 19
   - Right side: 2.8 * 0.2x + 2.8 * 5

2. Simplify the distributed terms:
   - Left side: 6x + 11.4
   - Right side: 0.56x + 14

3. Set the simplified expressions equal to each other:

   6x + 11.4 = 0.56x + 14

4. To solve for x, first get all terms involving x on one side and constant terms on the other:

   6x - 0.56x = 14 - 11.4

5. Simplify the equation:

   5.44x = 2.6

6. Divide by 5.44 to isolate x:

   x = 2.6 / 5.44

The solution for x can be calculated to give you the final answer.
Transcribed Image Text:The equation given is: 0.6(10x + 19) = 2.8(0.2x + 5) This equation can be solved by expanding both sides, combining like terms, and isolating the variable x. Here's how you can approach solving it: 1. Distribute the numbers outside the parentheses: - Left side: 0.6 * 10x + 0.6 * 19 - Right side: 2.8 * 0.2x + 2.8 * 5 2. Simplify the distributed terms: - Left side: 6x + 11.4 - Right side: 0.56x + 14 3. Set the simplified expressions equal to each other: 6x + 11.4 = 0.56x + 14 4. To solve for x, first get all terms involving x on one side and constant terms on the other: 6x - 0.56x = 14 - 11.4 5. Simplify the equation: 5.44x = 2.6 6. Divide by 5.44 to isolate x: x = 2.6 / 5.44 The solution for x can be calculated to give you the final answer.
Expert Solution
Step 1

Determine the value of X.

 

The value of X is obtained by solving the given equation below as follows:

 

From the information, given the equation is,

Probability homework question answer, step 1, image 1

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