in Wednesday'sP(Thurs.) = 0.39,mail. In actuality,Friday, orA library subscribes to two different weekly news magazines, each of which is supposed to arriveeach one may arrive on Wednesday, Thursday,Saturday. Suppose the two arrive independently of one another, and for each one P(Wed.) = 0.29,P(Fri.) = 0.19, and P(Sat.) = 0.13. Let Y= the number of days beyondWednesday that it takes for both magazines to arrive (so possible Y values are 0, 1, 2, or 3). Compute the pmf of Y. [Hint: There are 16 possible outcomes; Y(W,W) = 0, Y(F,Th) = 2, and so on.](Enter your answers to four decimal places.)0P(Y)3

Let's the events be,The corresponding probabilities are,Let Y be the number of days beyond Wednesday…

Answered: 0.39, -Compute the pmf of Y.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Step 1: We first define the event and corresponding probability

Let's the events be,

$W minus W e d n e s d a y T minus T h u r s d a y space F minus F r i d a y space space S minus S a t u r d a y$

The corresponding probabilities are,

$P left parenthesis W right parenthesis equals 0.29 P left parenthesis T right parenthesis equals 0.39 P left parenthesis F right parenthesis equals 0.19 P left parenthesis S right parenthesis equals 0.13$

Let Y be the number of days beyond Wednesday that it takes for both magazines to arrive (so possible Y values are 0, 1, 2, or 3)

The possible number of outcomes are $4 squared equals 16$

$left parenthesis W comma W right parenthesis comma left parenthesis W comma T right parenthesis comma left parenthesis W comma F right parenthesis comma left parenthesis W comma S right parenthesis left parenthesis T comma W right parenthesis comma left parenthesis T comma T right parenthesis comma left parenthesis T comma F right parenthesis comma left parenthesis T comma S right parenthesis left parenthesis F comma W right parenthesis comma left parenthesis F comma T right parenthesis comma left parenthesis F comma F right parenthesis comma left parenthesis F comma S right parenthesis left parenthesis S comma W right parenthesis comma left parenthesis S comma T right parenthesis comma left parenthesis S comma F right parenthesis comma left parenthesis S comma S right parenthesis$

the value associated for each of the outcomes follows:

$Y left parenthesis W comma W right parenthesis equals 0 comma space space space space space Y left parenthesis W comma T right parenthesis equals 1 comma space space space space space space space Y left parenthesis W comma F right parenthesis equals 2 comma space space space space Y left parenthesis W comma S right parenthesis equals 3 Y left parenthesis T comma W right parenthesis equals 1 comma space space space space space space Y left parenthesis T comma T right parenthesis equals 1 comma space space space space space space space space Y left parenthesis T comma F right parenthesis equals 2 comma space space space space space space Y left parenthesis T comma S right parenthesis equals 3 Y left parenthesis F comma W right parenthesis equals 2 comma space space space space space space Y left parenthesis F comma T right parenthesis equals 2 comma space space space space space space space space Y left parenthesis F comma F right parenthesis equals 2 comma space space space space space space Y left parenthesis F comma S right parenthesis equals 3 Y left parenthesis S comma W right parenthesis equals 3 comma space space space space space Y left parenthesis S comma T right parenthesis equals 3 comma space space space space space space space space Y left parenthesis S comma F right parenthesis equals 3 comma space space space space space space space Y left parenthesis S comma S right parenthesis equals 3$