0.279 g of the hydrate CoCl2•nH2O is heated to produce 0.197 g of anhydrous CoCl2 (MM = 129.83 g/mol). We want to use this to determine n, how many waters of hydration were in the original sample, be the end of the questions that follow. How many grams of water were in the original 0.279 g of hydrate?
0.279 g of the hydrate CoCl2•nH2O is heated to produce 0.197 g of anhydrous CoCl2 (MM = 129.83 g/mol). We want to use this to determine n, how many waters of hydration were in the original sample, be the end of the questions that follow. How many grams of water were in the original 0.279 g of hydrate?
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0.279 g of the hydrate CoCl2•nH2O is heated to produce 0.197 g of anhydrous CoCl2 (MM = 129.83 g/mol). We want to use this to determine n, how many waters of hydration were in the original sample, be the end of the questions that follow.
How many grams of water were in the original 0.279 g of hydrate?
Expert Solution
Step 1
Given:
Mass of hydrate = 0.279 g
Mass of anhydrous CoCl2 = 0.197 g
Molar mass of CoCl2 = 129.83 g/mol
Molar mass of water = 18.02 g/mol
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