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0.250 mol of K₂ CrO and 0.250 mol of NaSO are added to enough water to make 1.0 L of 4 solution. A Ba(NO3), solution is slowly added to this solution. What precipitate will form first? A. O BaSO4 B. O Na₂SO4 C. OK,SO D.O BaCrO4 E. OK,Cro F. O Na,CrO

0.250 mol of K₂ CrO and 0.250 mol of NaSO are added to enough water to make 1.0 L of 4 solution. A Ba(NO3), solution is slowly added to this solution. What precipitate will form first? A. O BaSO4 B. O Na₂SO4 C. OK,SO D.O BaCrO4 E. OK,Cro F. O Na,CrO

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Statement:** A solution is prepared by adding 0.250 mol of K₂CrO₄ and 0.250 mol of Na₂SO₄ to enough water to make 1.0 L of solution. A Ba(NO₃)₂ solution is then slowly added to this mixture. **Question:** What precipitate will form first as the Ba(NO₃)₂ solution is added? **Options:** A. BaSO₄ B. Na₂SO₄ C. K₂SO₄ D. BaCrO₄ E. K₂CrO₄ F. Na₂CrO₄ *Note: The question involves determining the order of precipitation based on solubility rules and the solubility product constants (Ksp) of potential precipitates.*
Transcribed Image Text:**Problem Statement:** A solution is prepared by adding 0.250 mol of K₂CrO₄ and 0.250 mol of Na₂SO₄ to enough water to make 1.0 L of solution. A Ba(NO₃)₂ solution is then slowly added to this mixture. **Question:** What precipitate will form first as the Ba(NO₃)₂ solution is added? **Options:** A. BaSO₄ B. Na₂SO₄ C. K₂SO₄ D. BaCrO₄ E. K₂CrO₄ F. Na₂CrO₄ *Note: The question involves determining the order of precipitation based on solubility rules and the solubility product constants (Ksp) of potential precipitates.*
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