Use the accompanying radiation levels inWfor 50 different cell phones. Find the percentile corresponding to 0.62kgClick the icon to view the radiation levels.Radiation levelsThe percentile corresponding to 0.62is0.25 0.26 0.27 0.49 0.62 0.63 0.63 0.64 0.71 0.84 Okg0.88 0.92 0.93 0.94 0.96 0.96 0.97 1.03 1.06 1.08(Round to the nearest whole number as needed.)1.11 1.13 1.14 1.14 1.16 1.17 1.181.19 1.19 1.191.211.22 1.23 1.25 1.26 1.28 1.28 1.30 1.32 1.341.36 1.36 1.36 1.39 1.43 1.48 1.511.52 1.53 1.55

Answered: 0.25 0.26 0.27 0.49 0.62 0.63 0.63 0.64…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Alison has all her money invested in two mutual funds, A and B. She knows that there is a 65% chance that fund A will rise in price, and a 70% chance that fund B will rise in price given that fund A rises in price. What is the probability that both fund A and fund B will rise in price?
Blue 0.143 Freckles 0.030 eyes No Freckles 0.857 0.182 Black 0.047 Green hair eyes 0.818 0.018 0.923 Brown eyes 0.982 0.278 0.061 Blue 0.259 eyes 0.722 0.232 Brown 0.327 Green hair eyes 0.768 0.153 Brown 0.461 0.414 eyes Caucasian 0.847 child 0.319 Blue 0.562 0.453 eyes 0.681 0.315 Green 0.302 Blonde hair eyes 0.698 0.164 Brown 0.123 eyes 0.025 0.836 0.857 Blue 0.473 eyes 0.143 0.767 Green Red hair 0.405 eyes 0.233 0.778 Brown 0.122 eyes 0.222
Vermont 8.67 New Hampshire 8.84 Maine 9.20 Connecticut 9.72 Rhode Island 9.94 Massachusetts 10.01 Oregon 10.07 West Virginia 10.00 Florida 10.40 Pennsylvania 10.59 Montana 10.84 Delaware 10.98 New Mexico 10.99 Michigan 11.01 Colorado 11.04 South Carolina 11.15 Arizona 11.26 New Jersey 11.36 Wyoming 11.36 Washington 11.42 North Carolina 11.46 California 11.50 Ohio 11.56 New York 11.58 Virginia 11.72 Nevada 11.76 Maryland 11.76 Alabama 11.82 Tennessee 11.93 Hawaii 11.95 Missouri 11.96 Iowa 11.97 Georgia 11.99 Minnesota 12.00 Kentucky 12.07 Indiana 12.20 Idaho 12.20 Arkansas 12.28 Mississippi 12.39 Kansas 12.45 Oklahoma 12.63 Louisiana 12.79 District of Columbia 13.11 Texas 13.19 Nebraska 13.21 South Dakota 13.48 Alaska 13.68 North Dakota 13.99 Wisconsin 11.03 Utah 14.93 Determine the mean and standard deviation of your sample. Find the 80%, 95%, and 99% confidence…
Amount 20.50 14.63 23.77 29.96 29.49 32.70 9.20 20.89 28.87 15.78 18.16 12.16 11.22 16.43 17.66 9.59 18.89 19.88 23.11 20.11 20.34 20.08 30.36 21.79 21.18 19.22 34.13 27.49 36.55 18.37 32.27 12.63 25.53 27.71 33.81 21.79 19.16 26.35 20.01 26.85 13.63 17.22 13.17 20.12 22.11 22.47 20.36 35.47 11.85 17.88 6.83 30.99 14.62 18.38 26.85 25.10 27.55 25.87 14.37 15.61 26.46 24.24 16.66 20.85
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1048 and x = 568 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. Standard Normal (z) Distribution a) Find the best point estimate of the population proportion p. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 (Round to three decimal places as needed.) 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 0.0 0.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.1 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 0.2 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.3 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.4 0.5 .6915 .6950 .6985 7019 .7054 .7088 .7123 .7157 .7190 .7224 0.5 0.6 .7257 .7291 7324 7357 .7389 .7422 .7454 .7486 .7517 .7549 0.6 0.7 .7580 .7611 .7642 7673 7704 .7734 .7764 .7794…
Use the magnitudes (Richter scale) of the earthquakes listed in the data set below. Find the mean and median of this data set. Is the magnitude of an earthquake measuring 7.0 on the Richter scale an outlier (data value that is very far away from the others) when considered in the context of the sample data given in this data set? Explain. Click the icon to view the earthquake Richter scale data. Find the mean and median of the data set using a calculator or similar data analysis technology. The mean of the data set is . (Round to three decimal places as needed.) The median of the data set is. (Round to three decimal places as needed.) Is the magnitude of an earthquake measuring 7.0 on the Richter scale an outlier when considered in the context of the sample data given? O A. No, because this value is not very far away from all of the other data values. B. Yes, because this value is very far away from all of the other data values. O C. Yes, because this value is the maximum data value. O…
First Die 4 6. 1 3 4 6. 7 3 4 5. 6. 7. 8. 4 5. 6. 7 8. 9. 4 6. 7. 8. 9. 10 5 6. 8 6. 10 11 8. 9. 10 11 12 419 t in 47 Second Die
W L 1.4 1.91.4 1.81.5 1.91.9 2.32.1 3.52.1 2.82.1 2.72.2 3.02.2 2.72.3 3.02.4 3.22.4 2.92.5 3.52.5 3.32.6 3.52.6 3.42.6 3.42.7 3.22.8 3.82.8 3.52.9 3.82.9 3.92.9 3.82.9 3.73.0 3.83.0 4.03.0 3.73.1 4.13.4 4.43.4 4.33.5 4.53.6 4.63.6 4.83.6 4.93.6 4.53.7 4.93.9 5.43.9 5.24.1 5.34.1 5.44.1 5.24.2 5.44.2 5.54.2 5.64.2 5.24.3 5.64.7 6.14.8 6.64.8 6.14.8 6.04.9 6.15.0 6.65.0 6.25.1 6.65.2 6.45.2 6.85.4 6.35.6 7.05.6 7.95.8 7.45.8 7.45.8 6.95.9 7.96.0 7.76.0 7.86.0 7.36.2 8.56.2 7.56.3 7.66.5 9.36.6 8.16.6 8.06.7 8.26.7 9.26.7 8.06.7 7.96.9 8.66.9 8.17.0 9.57.1 9.17.1 9.17.1 9.47.2 8.47.3 9.37.3 8.97.4 8.97.5 8.6 match the number to the corresponding residual
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle. y = 4x, y = 7x2 y y 2.5 0.1 0.2 0.3 0.4 0.5 0.6 2.0 -0.5- 1.5 -1.0 1.0 -1.5 0.5 -2.0 0.5 O -2.5- 0.1 0.2 0.3 0.4 0.6 y 2.5 0.2 0.3 0.4 0.5 0.6 2.0-
Lower class 0.08 0.33 0.58 0.75 0.83 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 4 5 5 5 5 5 5 6 6 7 7 7 7 7 7 7 8 8 8 8 9 9 9 9 9 9 9 9 10 10 10 10 10 10 11 11 11 11 12 12 13 14 14 14 14 14 14 15 15 15 15 15 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 17 17 17 17 17 17 17 17 17 17 17 17 17 17 17 17 17 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 18 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 19 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20…
A random sample of size n=4 packages is chosen from a Fedex courier. Assume that weights follow a normal distribution and that we observe the following weights in gms. 104,995,510,854 A 951% confidence interval for the population mean is
In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.2 and a standard deviation of 17.5. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. C What is the confidence interval estimate of the population mean µ? mg/dL <μ< mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits do not contain 0, suggesting…

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0.25 0.26 0.27 0.49 0.62 0.63 0.63 0.64 0.71 0.84 D 0.88 0.92 0.93 0.94 0.96 0.96 0.97 1.03 1.06 1.08 1.11 1.13 1.14 1.14 1.16 1.17 1.18 1.19 1.19 1.19 1.21 1.22 1.23 1.25 1.26 1.28 1.28 1.30 1.32 1.34 1.36 1.36 1.36 1.39 1.43 1.48 1.51 1.52 1.53 1.55