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0.20 Given the network in Fig. P9.20, show that the power supplied by the sources is equal to the power absorbed by the passive elements. 2/0° A+ Figure P9.20 ww -j2j312 49 + 6/45° V

0.20 Given the network in Fig. P9.20, show that the power supplied by the sources is equal to the power absorbed by the passive elements. 2/0° A+ Figure P9.20 ww -j2j312 49 + 6/45° V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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answer to this should be 6.7 W = 6.7 W. but need help with showing work. 

**9.20** Given the network in Fig. P9.20, show that the power supplied by the sources is equal to the power absorbed by the passive elements. **Figure P9.20:** The given network includes a current source, a voltage source, a resistor, an inductor (with inductive reactance), and a capacitor (with capacitive reactance) connected in a specific arrangement. The components are described as follows: - A current source supplying \(2 \angle 0^\circ\) A is connected in series with a resistor of 4 Ω. - This series combination is connected to a parallel branch comprising an inductor with impedance \(j3 \, \Omega\) and a capacitor with impedance \(-j2 \, \Omega\). - Finally, a voltage source supplying \(6 \angle 45^\circ\) V is connected across the parallel branch. The task is to show that the power supplied by the sources (current source and voltage source) is equal to the power absorbed by the passive elements (resistor, inductor, and capacitor) in this network. ### Detailed Explanation of the Diagram: - **Current Source (Left):** It is depicted with a circle and an arrow inside pointing upward, labeled \(2 \angle 0^\circ\) A. - **Resistor (Bottom):** Shown as a zigzag line with a label of \(4 Ω\). - **Inductor (Top Right Branch):** Represented by a coiled line with a label \(j3 Ω\). - **Capacitor (Top Middle Branch):** Represented by a straight line with perpendicular connectors and a label \(-j2 Ω\). - **Voltage Source (Right):** Depicted as a circle with a positive (+) and negative (-) sign inside, labeled \(6 \angle 45^\circ\) V. The network is structured with the current source and resistor in series while the inductor and capacitor are in parallel with each other, and both parallel branches are connected to the voltage source at the ends.
Transcribed Image Text:**9.20** Given the network in Fig. P9.20, show that the power supplied by the sources is equal to the power absorbed by the passive elements. **Figure P9.20:** The given network includes a current source, a voltage source, a resistor, an inductor (with inductive reactance), and a capacitor (with capacitive reactance) connected in a specific arrangement. The components are described as follows: - A current source supplying \(2 \angle 0^\circ\) A is connected in series with a resistor of 4 Ω. - This series combination is connected to a parallel branch comprising an inductor with impedance \(j3 \, \Omega\) and a capacitor with impedance \(-j2 \, \Omega\). - Finally, a voltage source supplying \(6 \angle 45^\circ\) V is connected across the parallel branch. The task is to show that the power supplied by the sources (current source and voltage source) is equal to the power absorbed by the passive elements (resistor, inductor, and capacitor) in this network. ### Detailed Explanation of the Diagram: - **Current Source (Left):** It is depicted with a circle and an arrow inside pointing upward, labeled \(2 \angle 0^\circ\) A. - **Resistor (Bottom):** Shown as a zigzag line with a label of \(4 Ω\). - **Inductor (Top Right Branch):** Represented by a coiled line with a label \(j3 Ω\). - **Capacitor (Top Middle Branch):** Represented by a straight line with perpendicular connectors and a label \(-j2 Ω\). - **Voltage Source (Right):** Depicted as a circle with a positive (+) and negative (-) sign inside, labeled \(6 \angle 45^\circ\) V. The network is structured with the current source and resistor in series while the inductor and capacitor are in parallel with each other, and both parallel branches are connected to the voltage source at the ends.
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