0.2 Is q = 0.6 0.4 0.2 a steady-state vector for A = ? Justify your answer. 0.6 0.8 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The vector q is a steady state vector because the sum of its entries is 1 and Aq = q. B. The vector q is not a steady state vector because the sum of its entries is (Type an integer or a decimal.) C. The vector q is not a steady state vector because Aq = (Type an integer or decimal for each matrix element.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Text on Image:**

Is \( \mathbf{q} = \begin{bmatrix} 0.2 \\ 0.6 \end{bmatrix} \) a steady-state vector for \( A = \begin{bmatrix} 0.4 & 0.2 \\ 0.6 & 0.8 \end{bmatrix} \)? Justify your answer.

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

- A. The vector \(\mathbf{q}\) is a steady-state vector because the sum of its entries is 1 and \( A\mathbf{q} = \mathbf{q} \).

- B. The vector \(\mathbf{q}\) is not a steady-state vector because the sum of its entries is \(\underline{\hspace{1cm}}\).  
  (Type an integer or a decimal.)

- C. The vector \(\mathbf{q}\) is not a steady-state vector because \( A\mathbf{q} = \underline{\hspace{1cm}} \).  
  (Type an integer or decimal for each matrix element.)
Transcribed Image Text:**Text on Image:** Is \( \mathbf{q} = \begin{bmatrix} 0.2 \\ 0.6 \end{bmatrix} \) a steady-state vector for \( A = \begin{bmatrix} 0.4 & 0.2 \\ 0.6 & 0.8 \end{bmatrix} \)? Justify your answer. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. - A. The vector \(\mathbf{q}\) is a steady-state vector because the sum of its entries is 1 and \( A\mathbf{q} = \mathbf{q} \). - B. The vector \(\mathbf{q}\) is not a steady-state vector because the sum of its entries is \(\underline{\hspace{1cm}}\). (Type an integer or a decimal.) - C. The vector \(\mathbf{q}\) is not a steady-state vector because \( A\mathbf{q} = \underline{\hspace{1cm}} \). (Type an integer or decimal for each matrix element.)
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