0.100 molar NaUH. We find that at the equivalence point, when we have added 25.0 mL of 0.100 molar NaOH, the pH is 9.5. We want to find the pka. The first step is to fill in this ICE chart. What do we put in for x in this chart?

0.100 molar NaUH. We find that at the equivalence point, when we have added 25.0 mL of 0.100 molar NaOH, the pH is 9.5. We want to find the pka. The first step is to fill in this ICE chart. What do we put in for x in this chart?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

We are titrating 25.0 mL 0.100 molar weak acid HA with
0.100 molar NaOH.
We find that at the equivalence point, when we have added
25.0 mL of 0.100 molar NaOH,
the pH is 9.5.
We want to find the pka. The first step is to fill in this ICE
chart.
What do we put in for x in this chart?
Hint, find pOH (14- pH) Then, [OH-] is 10^-pOH
[OH-] is x
(You do NOT have to do it, but would you know how to get pka
now?? Hint, you would need to find pKb)
C
E
A- (+ H2O)
0.050 M
© 2.5x106
O 1.5 x 10-3
○ 2.9 x 10-4
3.1 x 10-5
0.012
0.050 M-X
<=>
0
X
HA
OH-
0
X

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