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(0.1) = (0.2) = (0.3) = (0.4) = d) Find the solution y = ¢(t) of the given problem and evaluate 5(t) at t = 0.1,0.2, 0.3 and 0.4. v(t) = NOTE: Round your answer to five decimal places. (0.1) = (0.2) = (0.3) = (0.4)

(0.1) = (0.2) = (0.3) = (0.4) = d) Find the solution y = ¢(t) of the given problem and evaluate 5(t) at t = 0.1,0.2, 0.3 and 0.4. v(t) = NOTE: Round your answer to five decimal places. (0.1) = (0.2) = (0.3) = (0.4)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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y = 8+t – y; y(0) = 1 (a) Find approximate values of the solution of the given initial value problem at t = 0.1,0.2,0.3 and 0.4 using the Euler method with h = 0.1. NOTE: Round your answer to two decimal places. y(0.1) = y(0.2) = y(0.3) = y(0.4) - (d) Find the solution y = ¢(t) of the given problem and evaluate %3D $(t) at t = 0.1,0.2, 0.3 and 0.4. y(t) NOTE: Round your answer to five decimal places. y(0.1) = y(0.2) = y(0.3) = y(0.4) =
Transcribed Image Text:y = 8+t – y; y(0) = 1 (a) Find approximate values of the solution of the given initial value problem at t = 0.1,0.2,0.3 and 0.4 using the Euler method with h = 0.1. NOTE: Round your answer to two decimal places. y(0.1) = y(0.2) = y(0.3) = y(0.4) - (d) Find the solution y = ¢(t) of the given problem and evaluate %3D $(t) at t = 0.1,0.2, 0.3 and 0.4. y(t) NOTE: Round your answer to five decimal places. y(0.1) = y(0.2) = y(0.3) = y(0.4) =
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