VA = (8.988 x 10° N. m²/C")(0.0500 m:-791 V0.0500 mTwo point charges g1 = 2.40 nC and q2 = -6.80 nC are 0.100 m apart. Point Ais midway between them; point B is 0.0800 m from q1 and 0.0600 m from q2(Figure 1). Take the electric potential to be zero at infinity.Part BFor related problemsolving tips and strategies, you may want to view a VideoTutor Solution of Potential and potential energy.Find the potential at point B.Express your answer in volts.VB = -749 VSubmitPrevious Answersv Correct142VB4TE)-6.80 nCVB = (8.988 x 10° N - m² /C²)( 0.0800 m2.40 nC+= -749 V0.0600 mPart CFind the work done by the electric field on a charge of 3.00 nC that travels from point B to point AFigure< 1 of 1Express your answer in joules.Vol AEo?ВW =JSubmitPrevious Answers Request Answer0.080 mX Incorrect; Try Again; 7 attempts remaining0.050 m→<0.050 m-A92-0.060 m→

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Answered: 0.0500 m 0.0500 m/ Two point charges q…

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I am stuck on this physics homework, any help would be great!
Part A A 10.0 nC charge is at æ = Ocm and a -1.5 nC charge is at x = 5 cm At what point or points on the x-axis is the electric potential zero? Express your answer using two significant figures. If there is more than one answer, give each answer separated by a comma. cm Submit Request Answer Provide Feedback
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Part A Two stationary positive point charges, charge 1 of magnitude 3.85 nC and charge 2 of magnitude 1.70 nC are separated by a distance of 39.0 cm An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed vfinal of the electron when it is 10.0 cm from charge 1? Express your answer in meters per second. > View Available Hint(s) ΑΣφ Ufinal m/s
Item 9 A point charge with charge q1 = 2.80 μC is held stationary at the origin. A second point charge with charge q2 = -4.70 μC moves from the point (0.125 m, 0) to the point (0.250 m, 0.270 m ). Part A How much work is done by the electrostatic force on the moving point charge? Express your answer in joules. ► View Available Hint(s) W = 0.62558 Submit - ΑΣΦ Provide Feedback Previous Answers ? X Incorrect; Try Again; One attempt remaining J
Part A A +4.0 µC charge is 22 cm to the right of a -7.8 µC charge. Determine the potential at the midpoint between the two charges. Express your answer to two significant figures and include the appropriate units. µẢ Vmid = Value Units Submit Request Answer Part B Determine the direction of the electric field at the midpoint between the two charges. O to the left. O to the right. Submit Previous Answers v Correct Part C Determine the magnitude of the electric field at the midpoint between the two charges. Express your answer to two significant figures and include the appropriate units. µA ? Emid = Value Units
Part A How far must the point charges qi = 7.10 µC and q2 = -26.1 µC be separated for the electric potential energy of the system to be -166 J ? r = cm Submit Request Answer Provide Feedback Next >
Part B: Rectangle Three point charges (the charge for each is shown in terms of Q) are arranged at the corners of a rectangle as shown in the figure below. What is the potential at the fourth corner (point P)? Express your answer in terms of k, Q, & L. Ф= -70 2L 20 5L -9Q
Part A The work done by an external force to move a -5.60 µC charge from point A to point B is 1.50x10-3 J. If the charge was started from rest and had 4.72x10-4 J of kinetic energy when it reached point B, what must be the potential difference between A and B? Express your answer with the appropriate units. HẢ ? VB – VA = Value Units
Part C: A point charge q3 = -5.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2? Express your answer with the appropriate units. Wab=__
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