0.05 sec The wavefunction of a mechanical wave on a string is described by: y(x,t) = 0.012sin(TX-100tt+2rt/3), where x and y are in meters and t is in seconds. The transverse velocity of an element on the string at the left end (x = 0), at time t = is: O -0.6v3n m/s O -0.6n m/s O +0.6v3r m/s () +0.6n m/s None of the listed In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration. e'max, to the maximum angular velocity, emax, is 2Tt S (-1). What is
0.05 sec The wavefunction of a mechanical wave on a string is described by: y(x,t) = 0.012sin(TX-100tt+2rt/3), where x and y are in meters and t is in seconds. The transverse velocity of an element on the string at the left end (x = 0), at time t = is: O -0.6v3n m/s O -0.6n m/s O +0.6v3r m/s () +0.6n m/s None of the listed In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration. e'max, to the maximum angular velocity, emax, is 2Tt S (-1). What is
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Transcribed Image Text:0.05 sec
The wavefunction of a mechanical wave on a string is described by: y(x,t) =
0.012sin(Tx-100rtt+2rt/3), where x and y are in meters and t is in seconds. The
transverse velocity of an element on the string at the left end (x = 0), at time t = 0
is:
O -0.6 3Tm/s
O-0.6t m/s
+0.6~3n m/s
+0.6t m/s
O None of the listed
n an oscillatory motion of a simple pendulum, the ratio of the maximum angular
acceleration.e'max, to the maximum angular velocity. Omax, is 2Tt s (-1). What is
O O0 0 O
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