A 455 V, DC separately excited motor drives a variable torque load TLresistances are 0.2 N and 145 N, respectively. The motor draws a line current of 9 A at the given load. If rotational losse isequal to Prot = 0.1 Pin, answer the following questions. The field voltage Vf =85 V.0.03 N at 1140 rpm speed. The armature and field1- Calculate the armature voltage to reduce the speed by75%.V = 341VM12- Calculate the armature voltage to operate the motor at theVtholding condition.VfV = 0VT3- Calculate the efficiency of the motor at rated condition.4- Calculate the efficiency of the motor for part 1.

“Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

= 0.03 N at 1140 rpm speed. The armature and field A 455 V, DC separately excited motor drives a variable torque load TL resistances are 0.2 N and 145 N, respectively. The motor draws a line current of 9 A at the given load. If rotational losse is equal to Prot = 0.1 Pin, answer the following questions. The field voltage Vf =85 V. 1- Calculate the armature voltage to reduce the speed by 75%. V = 341 V 2- Calculate the armature voltage to operate the motor at the M1 Vt holding condition. Vf V = 0 V 3- Calculate the efficiency of the motor at rated condition. 4- Calculate the efficiency of the motor for part 1.

= 0.03 N at 1140 rpm speed. The armature and field A 455 V, DC separately excited motor drives a variable torque load TL resistances are 0.2 N and 145 N, respectively. The motor draws a line current of 9 A at the given load. If rotational losse is equal to Prot = 0.1 Pin, answer the following questions. The field voltage Vf =85 V. 1- Calculate the armature voltage to reduce the speed by 75%. V = 341 V 2- Calculate the armature voltage to operate the motor at the M1 Vt holding condition. Vf V = 0 V 3- Calculate the efficiency of the motor at rated condition. 4- Calculate the efficiency of the motor for part 1.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A DC shunt generator delivers 45 A at a terminal voltage of 220 V. The armature and the shunt field resistances are 0.01 2 and 44N respectively. The stray losses are 375 W. What is percentage efficiency of the DC generator
A 220 V DC series motor runs drawing a current of 30 A from the supply. Armature and field circuit resistances are 0.4 and 0.1 respectively. The load torque varies as the square of the speed. The flux in the motor may be taken as being proportional to the armature current. To reduce the speed of the motor by 50% the resistance in ohms that should be added in series with the armature is
A series motor runs at 800 r/min when the voltage is 400 V and the current is 25 A. The armature resistance is 0.4 ohm and the Series field resistance is 0.2 ohm. Determine the following: (a) The constant of the motor. If the speed decreases to 600 r/min,the torque increases by 32% and the field increases by 10%, determine the following: (b) The new armature current. (c) The new field current. (d) The new total resistance of the motor in ohm. (e) The additional resistance inserted in series with the motor in ohm.
A dc generator has a field flux of 0.001 Wb and 4 poles. The machine operates with at shaft speed of 1,650 rpm. There are 500 turns in the armature coil. Compute the average induced voltage.
4 poles DC series motor fed from a 220V source coiled with ripple coil and the product has 4 78conductor. If the resistance of the product and the field coils, respectively, is 0.502 and 2592.) And the magnetic flux for each pole is 25 mb, find both the speed and the total torque of the motor when drawing a current of 40A
The DC shunt generator with the terminal voltage 300 V, armature drop 8 V and the each brush drop 2 V, then the value of generated emf is
A brushed DC motor has a permanent magnetic field of 1.3 T. The armature radius is 0.05 m. The current flowing through the windings is 2.4 A and this produces a torque of 0.14 Nm. Determine the length of the windings in the machine in m.
A triplex wave-wound armature is used in a 6-pole DC machine. The number of coils is 111 each of which contains 12 turns. The resistance of each turn is 0.0112. Its flux per pole is 0.038 Wb, and its rotational speed is 230 rpm Calculate the number of conductors in the machine Calculate the the number of current paths in the machine Calculate the constant K'
A 230 V dc series motor has an armature resistance of 0.2 ohm and field resistance of 0.1 ohm at rated voltage. The motor draws a line current of 40 amperes and runs at a speed of 1000 rpm. Find speed of the motor for line current of 20 A at 230 V. Assume that flux at 20 A line current is 60% of flux at 40 A line current.
A 22 kW, 230 V Series DC motor runs at 750 rev/min at full load and draws 110 A from the supply. The resistance of the armature is 0.1250 and the series field 0.0250. Calculate the speed when the load is reduced such that the input current reduces to 56 A. Assume that the useful flux per pole at 110 A is 23.9 mWb and the flux for 56 A is be 15.5 mWb.
An 8-pole DC machine has a simplex wave-wound armature containing 200 coils of 10 turns each. The resistance of each turn is 0.01 Ω. The flux per pole is 0.004 Wb. What is the internal resistance of the armature in ohms? What is the current absorbed by this machine in amperes at the instant it's connected to a 100 Vdc source? What is the internally generated torque produced by the armature of this machine in N-m at the instant it's connected to the 100 Vdc source? With the DC machine connected to the 100 Vdc source, what is the steady state angular speed of the machine in rpm? What is the internally generated voltage of the armature of this machine at steady state in volts?
A 250 V series motor has an armature resistance of 0.2 ohm and a series-fieldresistance of 0.18 ohm. If the speed is 6oo RPM when the current is 32 amps.What will be the motor speed when the load is reduced so that the current is18 amps, under which condition the percent flux change is 50 % of the percentcurrent change.