0.025 (-20+ j40)³ (j80) (-20+ j240) (-20-j160) =-(9.95×10-¹)-(7.129×10+)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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HI! This is part of a partial fraction solution. I do not understand how they went from the above fraction to the bottom simplification.
please give handwritten answer

Transcribed Image Text:0.025 (-20+ j40)³
(j80) (-20+ j240) (-20-j160)
=-(9.95×10)-j(7.129×10+)
||
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