0.0152 g Mg(OH)2 dissolve in 2.0 L of water, forming a saturated solution at 25 °C. What is the solubility product constant, Ksp? The molar mass of Mg(OH)2 is 58.316 g/mol. Ksp = [ ? ] x 10 ? 1
0.0152 g Mg(OH)2 dissolve in 2.0 L of water, forming a saturated solution at 25 °C. What is the solubility product constant, Ksp? The molar mass of Mg(OH)2 is 58.316 g/mol. Ksp = [ ? ] x 10 ? 1
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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![### Solubility Product Constant (K_sp) Calculation
**Problem Statement:**
0.0152 g of Mg(OH)₂ dissolves in 2.0 L of water, forming a saturated solution at 25°C. What is the solubility product constant, K_sp?
Given:
- The molar mass of Mg(OH)₂ is 58.316 g/mol.
**Formula:**
\[ K_{sp} = [?] \times 10^{[?]} \]
**Instructions:**
1. **Do not round until the end.**
2. Enter the values for the coefficient and exponent in their respective fields.
**Data Entry Fields:**
- **Coefficient (Green)**: [ ]
- **Exponent (Yellow)**: [ ]
**Interactive Component:**
- An input field labelled "Coefficient (Green)" for entering the coefficient.
- An input field labelled "Exponent (Yellow)" for entering the exponent.
- An "Enter" button to submit the values.
### Explanation:
To solve for the solubility product constant, K_sp, follow these steps:
1. **Calculate the number of moles of Mg(OH)₂:**
\[
\text{Moles of Mg(OH)}_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{0.0152 \text{ g}}{58.316 \text{ g/mol}}
\]
2. **Determine the concentration of Mg(OH)₂ in the solution:**
\[
\text{Concentration of Mg(OH)}_2 = \frac{\text{moles}}{2.0 \text{ L}}
\]
3. **Write the dissociation equation:**
\[
\text{Mg(OH)}_2 \rightleftharpoons \text{Mg}^{2+} + 2\text{OH}^-
\]
4. **Calculate the concentrations of the ions:**
- For each mole of Mg(OH)₂, it produces 1 mole of Mg²⁺ and 2 moles of OH⁻.
- The concentration of Mg²⁺ is equal to the concentration of Mg(OH)₂.
- The concentration of OH⁻ is twice the concentration of Mg(OH)₂.
5. **Calculate K_sp:**
\[
K_{](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F648f5d91-ee0b-41d6-9c63-6d9410af2e0d%2F7b362412-dcd8-412b-a75d-9808220e678f%2Frhi1d1r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Solubility Product Constant (K_sp) Calculation
**Problem Statement:**
0.0152 g of Mg(OH)₂ dissolves in 2.0 L of water, forming a saturated solution at 25°C. What is the solubility product constant, K_sp?
Given:
- The molar mass of Mg(OH)₂ is 58.316 g/mol.
**Formula:**
\[ K_{sp} = [?] \times 10^{[?]} \]
**Instructions:**
1. **Do not round until the end.**
2. Enter the values for the coefficient and exponent in their respective fields.
**Data Entry Fields:**
- **Coefficient (Green)**: [ ]
- **Exponent (Yellow)**: [ ]
**Interactive Component:**
- An input field labelled "Coefficient (Green)" for entering the coefficient.
- An input field labelled "Exponent (Yellow)" for entering the exponent.
- An "Enter" button to submit the values.
### Explanation:
To solve for the solubility product constant, K_sp, follow these steps:
1. **Calculate the number of moles of Mg(OH)₂:**
\[
\text{Moles of Mg(OH)}_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{0.0152 \text{ g}}{58.316 \text{ g/mol}}
\]
2. **Determine the concentration of Mg(OH)₂ in the solution:**
\[
\text{Concentration of Mg(OH)}_2 = \frac{\text{moles}}{2.0 \text{ L}}
\]
3. **Write the dissociation equation:**
\[
\text{Mg(OH)}_2 \rightleftharpoons \text{Mg}^{2+} + 2\text{OH}^-
\]
4. **Calculate the concentrations of the ions:**
- For each mole of Mg(OH)₂, it produces 1 mole of Mg²⁺ and 2 moles of OH⁻.
- The concentration of Mg²⁺ is equal to the concentration of Mg(OH)₂.
- The concentration of OH⁻ is twice the concentration of Mg(OH)₂.
5. **Calculate K_sp:**
\[
K_{
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