0.0152 g Mg(OH)2 dissolve in 2.0 L of water, forming a saturated solution at 25 °C. What is the solubility product constant, Ksp? The molar mass of Mg(OH)2 is 58.316 g/mol. Ksp = [ ? ] x 10 ? 1

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### Solubility Product Constant (K_sp) Calculation

**Problem Statement:**

0.0152 g of Mg(OH)₂ dissolves in 2.0 L of water, forming a saturated solution at 25°C. What is the solubility product constant, K_sp?

Given:
- The molar mass of Mg(OH)₂ is 58.316 g/mol.

**Formula:**

\[ K_{sp} = [?] \times 10^{[?]} \]

**Instructions:**

1. **Do not round until the end.**
2. Enter the values for the coefficient and exponent in their respective fields.

**Data Entry Fields:**

- **Coefficient (Green)**: [  ]
- **Exponent (Yellow)**: [  ]

**Interactive Component:**

- An input field labelled "Coefficient (Green)" for entering the coefficient.
- An input field labelled "Exponent (Yellow)" for entering the exponent.
- An "Enter" button to submit the values.

### Explanation:

To solve for the solubility product constant, K_sp, follow these steps:

1. **Calculate the number of moles of Mg(OH)₂:**
    \[
    \text{Moles of Mg(OH)}_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{0.0152 \text{ g}}{58.316 \text{ g/mol}}
    \]

2. **Determine the concentration of Mg(OH)₂ in the solution:**
    \[
    \text{Concentration of Mg(OH)}_2 = \frac{\text{moles}}{2.0 \text{ L}}
    \]

3. **Write the dissociation equation:**
    \[
    \text{Mg(OH)}_2 \rightleftharpoons \text{Mg}^{2+} + 2\text{OH}^-
    \]

4. **Calculate the concentrations of the ions:**
    - For each mole of Mg(OH)₂, it produces 1 mole of Mg²⁺ and 2 moles of OH⁻.
    - The concentration of Mg²⁺ is equal to the concentration of Mg(OH)₂.
    - The concentration of OH⁻ is twice the concentration of Mg(OH)₂.

5. **Calculate K_sp:**
    \[
    K_{
Transcribed Image Text:### Solubility Product Constant (K_sp) Calculation **Problem Statement:** 0.0152 g of Mg(OH)₂ dissolves in 2.0 L of water, forming a saturated solution at 25°C. What is the solubility product constant, K_sp? Given: - The molar mass of Mg(OH)₂ is 58.316 g/mol. **Formula:** \[ K_{sp} = [?] \times 10^{[?]} \] **Instructions:** 1. **Do not round until the end.** 2. Enter the values for the coefficient and exponent in their respective fields. **Data Entry Fields:** - **Coefficient (Green)**: [ ] - **Exponent (Yellow)**: [ ] **Interactive Component:** - An input field labelled "Coefficient (Green)" for entering the coefficient. - An input field labelled "Exponent (Yellow)" for entering the exponent. - An "Enter" button to submit the values. ### Explanation: To solve for the solubility product constant, K_sp, follow these steps: 1. **Calculate the number of moles of Mg(OH)₂:** \[ \text{Moles of Mg(OH)}_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{0.0152 \text{ g}}{58.316 \text{ g/mol}} \] 2. **Determine the concentration of Mg(OH)₂ in the solution:** \[ \text{Concentration of Mg(OH)}_2 = \frac{\text{moles}}{2.0 \text{ L}} \] 3. **Write the dissociation equation:** \[ \text{Mg(OH)}_2 \rightleftharpoons \text{Mg}^{2+} + 2\text{OH}^- \] 4. **Calculate the concentrations of the ions:** - For each mole of Mg(OH)₂, it produces 1 mole of Mg²⁺ and 2 moles of OH⁻. - The concentration of Mg²⁺ is equal to the concentration of Mg(OH)₂. - The concentration of OH⁻ is twice the concentration of Mg(OH)₂. 5. **Calculate K_sp:** \[ K_{
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