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0. Which two structures ionize with loss of bromide to form the same carbocation? Br Br Br 20 Br I II III IV (A) I and II (B) II and III IV

0. Which two structures ionize with loss of bromide to form the same carbocation? Br Br Br 20 Br I II III IV (A) I and II (B) II and III IV

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question: PQ-20. Which two structures ionize with the loss of bromide to form the same carbocation?** **Options:** - (A) I and II - (B) II and III - (C) I and IV - (D) III and IV **Structure Diagrams:** 1. **Structure I:** - A linear structure with a bromide (Br) atom attached to a secondary carbon in a chain. 2. **Structure II:** - A branched structure with a bromide (Br) atom attached to a more substituted carbon. 3. **Structure III:** - Similar to structure I, but with a different positioning of the bromide (Br) in the chain. 4. **Structure IV:** - Similar to structure II in branching, with bromide (Br) attached to a carbon atom participating in a double bond with another carbon. **Correct Answer: (C) I and IV** These structures are likely to ionize, losing bromide to form the same carbocation due to their similar carbon frameworks that allow rearrangement or delocalization of charge.
Transcribed Image Text:**Question: PQ-20. Which two structures ionize with the loss of bromide to form the same carbocation?** **Options:** - (A) I and II - (B) II and III - (C) I and IV - (D) III and IV **Structure Diagrams:** 1. **Structure I:** - A linear structure with a bromide (Br) atom attached to a secondary carbon in a chain. 2. **Structure II:** - A branched structure with a bromide (Br) atom attached to a more substituted carbon. 3. **Structure III:** - Similar to structure I, but with a different positioning of the bromide (Br) in the chain. 4. **Structure IV:** - Similar to structure II in branching, with bromide (Br) attached to a carbon atom participating in a double bond with another carbon. **Correct Answer: (C) I and IV** These structures are likely to ionize, losing bromide to form the same carbocation due to their similar carbon frameworks that allow rearrangement or delocalization of charge.
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