0. for the funchion f (x,4) = 3-x?- u?, find a unit tangent vector to the level curve at the point (3,5) that' -3 has a positive x component

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 26E
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Can someone help me understand what I am doing wrong on number 10 please?
V145
745
tor the function f(x,u)= xf+ Zxy + Sy?+ 4x - 24 +1, find a unit tangent
Nector to the level curve at the' poin't (-3,-4) that has a
o component
positive
2x +
104-2>
NF(-3;4) = < 2(-3) + 2(-4)+4, 2(-3)+ l0 (-A)-2)
く-b -8+4
3-10
b-40-2 >
48)
normal vector
48t+ (-10) =
10
ZA64
K.9790
.2040
48
2404
12404
0. for the function f(x,4) = 3-x*-yt
at the point (3,5) that'
find
a unit tangent vector to the level curve
1.
+3
has a positive x com ponent
(-3)?
t(3,5) =/3-3} - (s})-o -(2(3).-3) 3-(3)8-5P-0 E (-2,(5)--3)\
9
norma I vector =
- 30
9
3,8973
51451
9.
23.3333 =
.8575
Transcribed Image Text:V145 745 tor the function f(x,u)= xf+ Zxy + Sy?+ 4x - 24 +1, find a unit tangent Nector to the level curve at the' poin't (-3,-4) that has a o component positive 2x + 104-2> NF(-3;4) = < 2(-3) + 2(-4)+4, 2(-3)+ l0 (-A)-2) く-b -8+4 3-10 b-40-2 > 48) normal vector 48t+ (-10) = 10 ZA64 K.9790 .2040 48 2404 12404 0. for the function f(x,4) = 3-x*-yt at the point (3,5) that' find a unit tangent vector to the level curve 1. +3 has a positive x com ponent (-3)? t(3,5) =/3-3} - (s})-o -(2(3).-3) 3-(3)8-5P-0 E (-2,(5)--3)\ 9 norma I vector = - 30 9 3,8973 51451 9. 23.3333 = .8575
Expert Solution
Step 1

Given: fx,y=3-x2-y2-3 at P3,5​​​​​​​

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