0. Consider the matrix A =|0 -1 -1 and vectors x = 1 and y (-1 Let vector v be defined as v = (A - AT)y. Evaluate the scalar product x v. [Please enter your answer numerically in decimal format. You will be marked correct as long as what you enter is within 0.25 of the correct answer. So for example, if the correct answer is 6.78 then any input that lies between between 6.53 and 7.03 will be marked as correct.) Answer:
0. Consider the matrix A =|0 -1 -1 and vectors x = 1 and y (-1 Let vector v be defined as v = (A - AT)y. Evaluate the scalar product x v. [Please enter your answer numerically in decimal format. You will be marked correct as long as what you enter is within 0.25 of the correct answer. So for example, if the correct answer is 6.78 then any input that lies between between 6.53 and 7.03 will be marked as correct.) Answer:
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![1
Consider the matrix A =|0
-1 -1| and vectors x = 1 and y =
(-1
Let vector v be defined as v = (A – AT)y. Evaluate the scalar product x · v.
[Please enter your answer numerically in decimal format. You will be marked correct as long as what you enter is within 0.25 of the correct
answer. So for example, if the correct answer is 6.78 then any input that lies between between 6.53 and 7.03 will be marked as correct.]
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5eb58e0-9f12-4d90-aaca-51c7f1a7920f%2F36291472-44a6-42be-b6ed-1fed168dedc2%2Fd05up2g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1
Consider the matrix A =|0
-1 -1| and vectors x = 1 and y =
(-1
Let vector v be defined as v = (A – AT)y. Evaluate the scalar product x · v.
[Please enter your answer numerically in decimal format. You will be marked correct as long as what you enter is within 0.25 of the correct
answer. So for example, if the correct answer is 6.78 then any input that lies between between 6.53 and 7.03 will be marked as correct.]
Answer:
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