**Problem:**A student with a mass of 45 kg jumps off a high diving board. Using \(6.0 \times 10^{24}\) kg for the mass of the Earth, what is the acceleration of the Earth toward her as she accelerates toward the Earth with an acceleration of 9.81 m/s\(^2\)? *(Hint: Use Newton’s Third Law to determine the net gravitational force the student exerts on the Earth.)***Solution Explanation:**To solve this problem, we need to understand that according to Newton's Third Law, every action has an equal and opposite reaction. When the student exerts a force on the Earth by falling, the Earth exerts an equal and opposite force on the student.1. **Force exerted by the student:** - The force due to gravity on the student is given by \( F = m \times g \), where \( m = 45 \) kg and \( g = 9.81 \) m/s\(^2\). - Calculate the force: \( F = 45 \, \text{kg} \times 9.81 \, \text{m/s}^2 \).2. **Acceleration of the Earth:** - According to Newton’s Third Law, the same force \( F \) acts on the Earth. - Use the formula \( F = M \times a \), where \( M = 6.0 \times 10^{24} \) kg is the mass of the Earth, to find the Earth's acceleration \( a \). - Rearrange the formula to solve for \( a \): \( a = \frac{F}{M} \).By substituting the values calculated in the first step into this equation, you can determine the acceleration of the Earth.

Given data: Mass of the student is, m= 45 kg Acceleration of the student after the jump towards…

Answered: 0. A student with mass 45 kg jumps off…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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