0. A horizontally launched projectile lands 61.57m below the launch point and a horizontal distance of 141.00m from the launch point. What was its initial velocity? vx= ms *Round your answer to the nearest thousandth if necessary
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vx=
*Round your answer to the nearest thousandth if necessary.
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- PlzIn the figure, a baseball is hit at a height h = 1.30 m and then caught at the same height. It travels alongside a wall, moving up past the top of the wall 1.3 s after it is hit and then down past the top of the wall 3.3 s later, at distance D = 58 m farther along the wall. (a) What horizontal distance is traveled by the ball from hit to catch? What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's velocity just after being hit? (d) How high is the wall?A ball is tossed from upper-story window of a building. The ball is given an initial velocity at 8.0 m/s at an angle of 200 below the horizontal. It strikes the ground 3.0 s later. a.) How far horizontally from the base of the building does the ball strike the ground? b.) Find the height from which the ball was thrown. c.) How long does it take the ball to reach the point 10m below the level launching?
- Top Golf is a famous and well-known place for sports entertainment and family fun. Typically a building has two to three floors full of rooms for people to rent and relax in while they hit golf balls onto a 250-yard field. Suppose a person hits a golf ball from the second floor (h) with an initial velocity of 118 mph at a 15° angle (0). The golf ball is in the air for (t) secs and lands 170 (x) yards from its initial place. The path of the golf ball is depicted in figure 2. Hint: 1 mile 5280 ft, 1 yard = 3 ft = (i) How long does it take for the golf ball to land on the field in seconds? (t) (ii) At what height was the ball struck at in feet? (h) (iii) What is the maximum height the golf ball reaches in feet? (yax) Figure 2. V₂A ball thrown down the inclined strikes it at an inclined distance of 75m If the ball rises to a maximum height of 20m above the point of release. Compute the initial velocity and the projectile angle from horizontal (Say slope ofinclined is is 1V:3H) Choose the correct answer: a. 30m/sb. 54 3degc. 16.67m/sd. 24.4m/se. 43.2degf. 33.3degg.17.4m/sh. 45degi. 20.7m/sj. 23.6degA projectile is launched at ground level with an intial vertical velocity of 25.0m/s and a horizontal velocity of 43.3m/s. It strikes a target above the ground 3.00 seconds later. a) How high is the target above the gound? b) How far did the projectile travel before hitting the target? c) What is the horizontal component of the velocity of the projectile right as it hits the target? d) What is the vertical component of the velocity of the projectile right as it hits the target?
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- Emmanuel Zacchini launched as a human cannonball in 1940 soared over three Ferris wheels each 18.0 m high covering a horizontal distance of 10.63m. a.) Assuming that the point of projection is 2.50 m above the ground and that he landed safely on a net placed at the same level, find his initial velocity. b.) Assuming that he missed the net and landed on the ground, with what velocity will he strike the ground?Q1. An archer aims at the bullseye of a target 50.0 m away. The arrow is at the same height as the bullseye. If the archer angles the arrow upwards at 12°, what must the arrow's initial speed be in order to hit the bullseye?A projectile is projected from the origin with a velocity of 30.0 m/s at an angle of 45.0 degrees above the horizontal. What is the range of the projectile? O a. 144 m O b. 91.8 m O c. 48.5 m O d. 86.2 m