ち, 0 ≤t < 1, \19. y'+y=<2-t, 1≤t<2, y(0) = 0, y'′(0) = 0 0, 2≤t < 8;

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

19

OI WI
Ver corresponding ph
sections in this chapter are numerous initial-
al equations with constant coefficients. Many
cal systems, but usually we do not point this
m to solve
y(0) = 0,
ace transform 10. y" - 2y' + 2y = 0;
y"-2y' +4y=0;
11.
y(0) = 2,
12.
y" +2y' + 5y = 0;
y(0) = 2,
13. y(4) - 4y"" + 6y" - 4y' + y = 0; y(0) = 0,
y'(0) = 1, y"(0) = 0, y""(0) = 1
14. y(4) - y = 0; y(0) = 1, y'(0) = 0, y'(0) = 1,
y"(0) = 0
20 ai 1
of stemilipol ai ti S.1.0 msnood T
15. y" +w²y = cos(2t), w² #4; y(0) = 1, y'(0) = 0 dilw
16. y" - 2y' +2y=e¹; y(0) = 0, y'(0) = 1 word
17. y" + 4y =
In each of Problems 17 through 19, find the Laplace transform Y(s) =
L{y} of the solution of the given initial value problem. A method of
determining the inverse transform is developed in Section 6.3. You
may wish to refer to Problems 16 through 18 in Section 6.1. do 2
18. y" + 4y =
19. y" + y =
(@)))
y'(0) = 1
y'(0) = 0 molenen sosiga.l
y'(0) = −1
J IS
™,
0, π ≤t< 00;
1, 0≤t<π, vig
brs
D5
t, 0≤t < 1,
1, 1≤t<∞0;
8;
y(0) = 1, y'(0) = 0
y(0) = 0, y'(0) = 0
t,
0 ≤ t < 1,
2-t, 1≤t<2, y(0) = 0, y'(0) = 0
0,
2≤t<∞;
Transcribed Image Text:OI WI Ver corresponding ph sections in this chapter are numerous initial- al equations with constant coefficients. Many cal systems, but usually we do not point this m to solve y(0) = 0, ace transform 10. y" - 2y' + 2y = 0; y"-2y' +4y=0; 11. y(0) = 2, 12. y" +2y' + 5y = 0; y(0) = 2, 13. y(4) - 4y"" + 6y" - 4y' + y = 0; y(0) = 0, y'(0) = 1, y"(0) = 0, y""(0) = 1 14. y(4) - y = 0; y(0) = 1, y'(0) = 0, y'(0) = 1, y"(0) = 0 20 ai 1 of stemilipol ai ti S.1.0 msnood T 15. y" +w²y = cos(2t), w² #4; y(0) = 1, y'(0) = 0 dilw 16. y" - 2y' +2y=e¹; y(0) = 0, y'(0) = 1 word 17. y" + 4y = In each of Problems 17 through 19, find the Laplace transform Y(s) = L{y} of the solution of the given initial value problem. A method of determining the inverse transform is developed in Section 6.3. You may wish to refer to Problems 16 through 18 in Section 6.1. do 2 18. y" + 4y = 19. y" + y = (@))) y'(0) = 1 y'(0) = 0 molenen sosiga.l y'(0) = −1 J IS ™, 0, π ≤t< 00; 1, 0≤t<π, vig brs D5 t, 0≤t < 1, 1, 1≤t<∞0; 8; y(0) = 1, y'(0) = 0 y(0) = 0, y'(0) = 0 t, 0 ≤ t < 1, 2-t, 1≤t<2, y(0) = 0, y'(0) = 0 0, 2≤t<∞;
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