The answer is already there, just need a written explanation of how the answer was achieved and what's happening in a few sentences. (9.) ASxLight wave (6.0 × 10² hm) wave length fallsdouble shit and the 1sz 'darkon afringe of interference is observed to beat an angle of 12°, w the the horizontalCentral Line, the screen is 1.25m From the slits.a.) Draw missing information belowd. (include the wavethe=1201.25-md = (²+²) asin o+2D2 B11-1BOvÖD13=2Db.) find the seperation (d) of the shits.I sin = m+2) asincey-1,301ST Dark (1st min)(ort) (6.0.10²³).10-9m)(sin (120)p3rd Dok3rd minM=2-6C.) find the distance between the central bright Linem=0 and the 3rd- dark fringe.1y = a(m+ 2) = (6.0.107 m) (1.25m)(1-44-10-6m)Not 31.44.10m-(2 + 1/2) = 1.30 m

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