0= "D = °P 0.1 4. b = Sf()sin(n@,t) dt=: 4 |(30t-3)sin(5nzt )dt 0.4 30t - 3 : sin(5nnt) cos5nnt 30 5nn --sin5nnt 25n2n? rier (Series-integral-Transform) (30t-3)cos5nnt 30sin5nnt| 0.1 [30sin = 10 25n2n2 3 bn = 10 5nn 25n2n2 0. 5nn Then f (t) = En=1[10- 30sinn 3 Isin(5nat) 2. %3D1 25n2n2 No

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Related questions
Question
I need the answer as soon as possible
I want a detailed solution for integration
2Examples
Find Fourier series expansion of the following wave:
(fL4))(-0.1) = -34 +0.3
4-
Cリう
私 。こ3 0.3
-0.1
0s 0.3
5 0.2 03
3ot+3
%3D
T=0.4
3
Solution:
This function is odd?
2 = 57t
o.J
T=0:4, wo
rad/sec
To find f(t):
Q4
-3 Yezlo, -3)
y-yı
Y2-Y1
f(t) - 0
-3 – 0
where p:(0.1,0), P2 (0,-3)
%3D
XーX1
X2X1t- 0.1
0 - 0.1
: f(t) = 30t – 3 for 0<t< 0.1
do = a, = 0
0.1
4
4
b, =f(1)sin(nw,t) dt=
(80t-3)sin(5nzt)dt
0.4
dx
30t – 3 : sin(5nnt)
cos5nnt
30
5nn
--sin5nnt
25n2n2
urier (Series-integral-Transform)
(30t-3)cos5nnt
30sin-
2
= 10
25n2n2
= 10
30sin5nnt] 0.1
5nn
25n2n2
5nn
30sinn
2
Then f(t) = En=1[10-
25n2n2
3
]sin(5nnt)
2.
5nn
No
Transcribed Image Text:I want a detailed solution for integration 2Examples Find Fourier series expansion of the following wave: (fL4))(-0.1) = -34 +0.3 4- Cリう 私 。こ3 0.3 -0.1 0s 0.3 5 0.2 03 3ot+3 %3D T=0.4 3 Solution: This function is odd? 2 = 57t o.J T=0:4, wo rad/sec To find f(t): Q4 -3 Yezlo, -3) y-yı Y2-Y1 f(t) - 0 -3 – 0 where p:(0.1,0), P2 (0,-3) %3D XーX1 X2X1t- 0.1 0 - 0.1 : f(t) = 30t – 3 for 0<t< 0.1 do = a, = 0 0.1 4 4 b, =f(1)sin(nw,t) dt= (80t-3)sin(5nzt)dt 0.4 dx 30t – 3 : sin(5nnt) cos5nnt 30 5nn --sin5nnt 25n2n2 urier (Series-integral-Transform) (30t-3)cos5nnt 30sin- 2 = 10 25n2n2 = 10 30sin5nnt] 0.1 5nn 25n2n2 5nn 30sinn 2 Then f(t) = En=1[10- 25n2n2 3 ]sin(5nnt) 2. 5nn No
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