0 A cube with side length 12 cm is oriented parallel to the coordinate planes as shown. The cube is placed in an external electric field of E= 50i+60j N/C. Calculate the electric flux through the different sides of the cube. Hint: The x-component of the electric field acts left to right, since it is positive. The y- component of the electric field acts from bottom to top, since it is positive. Consider that the electric field has no z-component. Flux through the top side = Flux through the left side = Flux through the right side = Flux through the front side = 0 Submit Question (N*m²)/C (N*m²)/C (N*m²)/C (N*m²)/C

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Chapter1: Units, Trigonometry. And Vectors
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4
IDI
R
F
D
A cube with side length 12 cm is oriented parallel to the coordinate planes as shown. The cube is
placed in an external electric field of E= 50i+60j N/C. Calculate the electric flux through the
different sides of the cube.
Hint: The x-component of the electric field acts left to right, since it is positive. The y-
component of the electric field acts from bottom to top, since it is positive. Consider that the
electric field has no z-component.
V
Flux through the top side =
Flux through the left side =
Flux through the right side =
Flux through the front side = 0
Submit Question
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Transcribed Image Text:$ 4 IDI R F D A cube with side length 12 cm is oriented parallel to the coordinate planes as shown. The cube is placed in an external electric field of E= 50i+60j N/C. Calculate the electric flux through the different sides of the cube. Hint: The x-component of the electric field acts left to right, since it is positive. The y- component of the electric field acts from bottom to top, since it is positive. Consider that the electric field has no z-component. V Flux through the top side = Flux through the left side = Flux through the right side = Flux through the front side = 0 Submit Question % 5 T A 6 B Y G H 17 4- & (N*m²)/C (N*m²)/C (N*m²)/C (N*m²)/C + 8 M ( K ► 11 O L [ ? prt sc 4 delete backspace pause
Expert Solution
Step 1

The flux us given as the dot product of electric field vector and the area vector .

The direction of area vector is prependicularly outward of  the surface . If we are looking the cube from its exterior the area vector with each surface is directly outward from that surface .

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