0 = 30°. The box has a mass m = 4 kg, the coefficient of kinetic friction between the box the inclined is µ = 0.5, and the block moves a distance d = 10 m up the inclined plane. What is the work done by the force F? Answer: 400 J. a) b) What is the normal force from the inclined plane? Answer: 33.9 N c) What is the work done by the kinetic friction force? Answer: - 169.5 J d What is bu 106 1
0 = 30°. The box has a mass m = 4 kg, the coefficient of kinetic friction between the box the inclined is µ = 0.5, and the block moves a distance d = 10 m up the inclined plane. What is the work done by the force F? Answer: 400 J. a) b) What is the normal force from the inclined plane? Answer: 33.9 N c) What is the work done by the kinetic friction force? Answer: - 169.5 J d What is bu 106 1
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![In the figure below we have a force F = 40 N pushing a box up an inclined plane with an angle
0 = 30°. The box has a mass m = 4 kg, the coefficient of kinetic friction between the box and
the inclined is μ = 0.5, and the block moves a distance d = 10 m up the inclined plane.
a) What is the work done by the force F? Answer: 400 J.
b) What is the normal force from the inclined plane? Answer: 33.9 N
c) What is the work done by the kinetic friction force? Answer: - 169.5 J
d) What is the work done by the gravitational force? Answer: - 196 J
e) What is Wnet, the net work done on the box? Answer: 34.5 J
f) The box starts from rest. What is the speed of the box after it has travelled the distance
d = 10 m up the incline plane? Answer: 4.2 m/sec
F = 40 N
m = 4 kg
0 = 30°
Mk=0.5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F916b3e43-3e70-4159-b0c4-23957999f35d%2Ff14947d9-e203-4a9f-be8b-591be63f6c56%2F18fam4w_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In the figure below we have a force F = 40 N pushing a box up an inclined plane with an angle
0 = 30°. The box has a mass m = 4 kg, the coefficient of kinetic friction between the box and
the inclined is μ = 0.5, and the block moves a distance d = 10 m up the inclined plane.
a) What is the work done by the force F? Answer: 400 J.
b) What is the normal force from the inclined plane? Answer: 33.9 N
c) What is the work done by the kinetic friction force? Answer: - 169.5 J
d) What is the work done by the gravitational force? Answer: - 196 J
e) What is Wnet, the net work done on the box? Answer: 34.5 J
f) The box starts from rest. What is the speed of the box after it has travelled the distance
d = 10 m up the incline plane? Answer: 4.2 m/sec
F = 40 N
m = 4 kg
0 = 30°
Mk=0.5
![W = F₁Ax = ² · AX, Wnet = ½ m(v₁)² — ²/ m(v;)², W = ƒ Fxdx, W = S F · dř
F
S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F916b3e43-3e70-4159-b0c4-23957999f35d%2Ff14947d9-e203-4a9f-be8b-591be63f6c56%2Fhcq1zd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:W = F₁Ax = ² · AX, Wnet = ½ m(v₁)² — ²/ m(v;)², W = ƒ Fxdx, W = S F · dř
F
S
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1: Given Data:
Given
The mass of the box is
Applied force is
The angle of inclination is
The coefficient of kinetic friction between the box and the inclined plane is
Displacement of the box is
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