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0₂ 03 gas 600⁰ P + H* Which reduction below corresponds to the half-cell above? Select one: O a. O₂(g) + 4H+ + 4e2H₂O O b. C. 03(g) + 2H+ + 2e¯=0₂(g) + H₂O O₂(g) + H+ +eHO₂ O d. O₂(g) + 2H+ + 2e¯ ⇒ 2H₂O2

0₂ 03 gas 600⁰ P + H* Which reduction below corresponds to the half-cell above? Select one: O a. O₂(g) + 4H+ + 4e2H₂O O b. C. 03(g) + 2H+ + 2e¯=0₂(g) + H₂O O₂(g) + H+ +eHO₂ O d. O₂(g) + 2H+ + 2e¯ ⇒ 2H₂O2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image depicts an electrochemical cell setup. It features several key components: - **Gases**: O₂ and O₃ are labeled on the left side, indicating that oxygen and ozone gases are involved. - **Gas Bubbles**: Represented as circles within the electrolyte solution, indicating gas diffusion into the cell. - **Electrolyte**: The solution contains H⁺ ions, suggestive of an acidic environment. - **Electrode**: A red section labelled "Pt" represents a platinum electrode, typically used as an inert electrode in such reactions. - **Tubes**: Pipes are shown for gas intake and exhaust, colored in black and green. Below the diagram is a question regarding which reduction reaction corresponds to the half-cell illustrated. ### Question: **Which reduction below corresponds to the half-cell above?** **Select one:** - a. \( \text{O}_2(g) + 4\text{H}^+ + 4\text{e}^- \rightarrow 2\text{H}_2\text{O} \) - b. \( \text{O}_3(g) + 2\text{H}^+ + 2\text{e}^- \rightarrow \text{O}_2(g) + \text{H}_2\text{O} \) - c. \( \text{O}_2(g) + \text{H}^+ + \text{e}^- \rightarrow \text{HO}_2 \) - d. \( \text{O}_2(g) + 2\text{H}^+ + 2\text{e}^- \rightarrow 2\text{H}_2\text{O}_2 \)
Transcribed Image Text:The image depicts an electrochemical cell setup. It features several key components: - **Gases**: O₂ and O₃ are labeled on the left side, indicating that oxygen and ozone gases are involved. - **Gas Bubbles**: Represented as circles within the electrolyte solution, indicating gas diffusion into the cell. - **Electrolyte**: The solution contains H⁺ ions, suggestive of an acidic environment. - **Electrode**: A red section labelled "Pt" represents a platinum electrode, typically used as an inert electrode in such reactions. - **Tubes**: Pipes are shown for gas intake and exhaust, colored in black and green. Below the diagram is a question regarding which reduction reaction corresponds to the half-cell illustrated. ### Question: **Which reduction below corresponds to the half-cell above?** **Select one:** - a. \( \text{O}_2(g) + 4\text{H}^+ + 4\text{e}^- \rightarrow 2\text{H}_2\text{O} \) - b. \( \text{O}_3(g) + 2\text{H}^+ + 2\text{e}^- \rightarrow \text{O}_2(g) + \text{H}_2\text{O} \) - c. \( \text{O}_2(g) + \text{H}^+ + \text{e}^- \rightarrow \text{HO}_2 \) - d. \( \text{O}_2(g) + 2\text{H}^+ + 2\text{e}^- \rightarrow 2\text{H}_2\text{O}_2 \)
Expert Solution
Step 1

In the given half cell O3 and O2 gas is there and the medium is acidic as H+ ion is there in the solution. So reduction reaction must contain these three species. 

 

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