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(0) = 0 are (0) Q3: Iteration 2 by Gauss-Seidel iteration method, where x₁ = x₂ =X3 -2x1 + 7x2+2x3 = 5 6x1-2x2 + x3 = 11 x1 + 2x2-5x3 = -1 A) X₁ 2.0691 x₂=1.0121 x₁=1.0107 B) X₂=2.0691 x₂=1.0122 x₁=1.0147 C) x₁=3.0691 x₂= 1.1021 x₁=1.0157 D) X₂=2.7691 x₂= 1.0221 x₁=1.2147 E) X₂=2.0611 x₂= 2.0021 x₁=1.4147 F) X₂=2.0691 x₂=1.0021 x₁=1.0147

(0) = 0 are (0) Q3: Iteration 2 by Gauss-Seidel iteration method, where x₁ = x₂ =X3 -2x1 + 7x2+2x3 = 5 6x1-2x2 + x3 = 11 x1 + 2x2-5x3 = -1 A) X₁ 2.0691 x₂=1.0121 x₁=1.0107 B) X₂=2.0691 x₂=1.0122 x₁=1.0147 C) x₁=3.0691 x₂= 1.1021 x₁=1.0157 D) X₂=2.7691 x₂= 1.0221 x₁=1.2147 E) X₂=2.0611 x₂= 2.0021 x₁=1.4147 F) X₂=2.0691 x₂=1.0021 x₁=1.0147

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(0) (0) Q3: Iteration 2 by Gauss-Seidel iteration method, where x = x2 -2x1 + 7x2+2x3 = 5 6x1-2x2 + x3 = 11 x1 + 2x2-5x3 = -1 A) X₂=2.0691 x₂=1.0121 x 1.0107 B) X₂=2.0691 C) X₂=3.0691 x₂= 1.1021 x₂=1.0157 D) X₂=2.7691 E) X₂=2.0611 x₂= 2.0021 x₂=1.4147 F) X₁=2.0691 = (0) x) = 0 are x₂= 1.0122 x 1.0147 x₂= 1.0221 x₁=1.2147 x₂= 1.0021 x₂=1.0147
Transcribed Image Text:(0) (0) Q3: Iteration 2 by Gauss-Seidel iteration method, where x = x2 -2x1 + 7x2+2x3 = 5 6x1-2x2 + x3 = 11 x1 + 2x2-5x3 = -1 A) X₂=2.0691 x₂=1.0121 x 1.0107 B) X₂=2.0691 C) X₂=3.0691 x₂= 1.1021 x₂=1.0157 D) X₂=2.7691 E) X₂=2.0611 x₂= 2.0021 x₂=1.4147 F) X₁=2.0691 = (0) x) = 0 are x₂= 1.0122 x 1.0147 x₂= 1.0221 x₁=1.2147 x₂= 1.0021 x₂=1.0147
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