.Using mesh analysis, determine the loop currents (11, 12. 13) and load current at 40 and 10. 20 10 V 40 20 V 10 30 ww www
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- A certain impedance is given by 1012° N. Does the current lead or lag the voltage, and by how many degrees? Fill in the blanks. The current the voltage byThe total power drawn by the two-impedance load in parallel is 26kW at 0.98 power factor lagging, it is being supplied by a 230-volts AC source. One of the loads (Load 1) takes 16kVA at 0.77 power factor lagging. What is the reactive power of the unknown impedance (Load 2)?Please and thank you
- Problem 2 The circuit diagram of a certain load is presented below. Determine the following: a. The power factor of the load. b. If the load is connected across a 400 Vrms source, determine the real and reactive power consumed by the load. c. From (b), determine the value of the capacitor to be placed in parallel with the load in order to improve the power factor of the load to 95% lagging. From (b), A synchronous motor is installed in parallel with the load to correct the pf. The motor is rated 5 hp operating at 60% efficiency. Assuming that the motor is running at rated power. Determine the apparent power and power factor of the motor in order to improve the load's pf to 95% lagging. 202 500 µF HI + VL -20 mH 5Ω >0.5VL m 15 mHUse the information below to answer questions 24 und 25. The voltage across and the current through a load are (10+ j5Y and (2-jiArespecively. 24. What is the reactive power in VArconsumed? D. 0 A. 15 C. 20 D. 25 25. What is the pawer factor of the load? A. 0.8 leading B. 0.8 Jagging. -D. 0.6 ligging C 0.6 leadingPower factor correction is a method to do which of the following.
- Driving-point admittance The actual impedance of a load is 30 OHM. The per-unit impedance of the load is 0.5 pu when Base Voltage is 600 V and Base Power is of O 6000 VA O 8000 VA O2000 VA 4000 VA Jump to ncements MacBook Air DD DII F10 F9 F8 000 F7 F6128, An equipment has an impedance 0.9 p.u. to a base of 20 MVA, 33 kV. To the base of 50 MVA, 11 kV, the p.u. impedance will be (a) 4.7 (c) 0.9 (b) 20.25 (d) 6.75The Full-looad and No-load of a regulator are 5.2V and 5.3V, respectively. Then the % load regulation is а. 0.1% b. 2.63% C. 1.92% d. 5.3%
- Determine the value of the capacitor to be connected in parallel with ZL (load) in order to correct the power factor of the load to 0.90802.7. In the circuit below write the loop equations and set up (not solve) the matrix equation for the load current. Wiso 150 75 28 100When caluating the average power delivered to a bad by an AC sigre, it is not as straightforward as DC. It depere on the difference in phase between the sincecidal voltage across and current through the loadi, and it relates to the RMB values. The average power or enmetimas referred to as the active or real power, is related to the underpirning snusoidal voltage and current by P-Vene Cosy-00 W In this question there is only a resistive load, A-6.00 and the amplitude is 98V. Decame the amplitude of the curent through the load I- Workout the P 96V resistor, 6.80 50Hz V1 R1 6.80 Reset RUN/Stop Electric Potential Power Charge Simulation Speed Charge Flow Current Circuit: