Please solve Quickly C++ programming language .look at code below then fill the blanks;int a = 5, b = 2, c = 6, d = 4if (!b)%3!"cout << "A\nelse;"cout << "B\nif (a == b || c > d):"cout << "C\nelse:"cout << "D\n: the output isand

Here in this question we have given a c++ code..and we have asked the output of the program.

Answered: .look at code below then fill the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
C++
#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
Look at the following code. int x = 7; int *ptr = &x;What will be displayed if you send the expression *iptr to cout? What happens if you send the expression ptr to cout?
Determine all the output from the following program as it would appear on the screen. void func1(int); void func2(int = 4, int = 5, int = 2); int func3(int &, int, int); %3D int main() { int x = 0, z = 0, y = 2; func1(y); cout << y << endl; func2(x, y, z); func2(); func3(x, y, z); = Z func1(x); cout << x << " " << y << " " << z << endl; return 0; } void func1(int b) { static int a;
C++: Describe how the following call by reference works. Make a comment for each line. void pxc(int& c, int& d) { int k = c; c = d; d = k; } int main() { int a = 15, b = 100; pxc(a, b); }
Text-based adventure game: Pretend you are creating a text-based adventure game. At different points in the game, you want the user to select to fight, run, or hide from certain enemies. Modify the application below (week3.py) so that the selection variable is sent as an argument into the choice() function. The user should enter 1 to fight, 2 to run, or 3 to hide in the main(). The choice() function should print one of the three options. You will need to add an if statement in the choice() function to make the correct selection.
Enter integer: 4 You entered: 4 4 squared is 16 And 4 cubed is 64!! Enter another integer: 5 4 + 5 is 9 4 * 5 is 20 =================================== #include <stdio.h> int main(void) { int userNum; int userNum2; printf("Enter integer:\n"); scanf("%d",&userNum); printf("You entered: "); printf( "%d", userNum); printf("\n"); printf("%d", userNum); printf( " squared is "); printf("%d", userNum * userNum); printf("\n"); printf("And "); printf("%d", userNum); printf(" cubed is "); printf("%d", userNum * userNum * userNum); printf("!!"); printf("\n" "Enter another integer:\n"); scanf("%d",&userNum2); printf("\n"); printf("%d", userNum2); return 0;}
I assume the following 2 codes express the same meaning? int myvar; int * myptr = &myvar; and int myvar; int * myptr; myptr = &myvar;
H7.

SEE MORE QUESTIONS

Recommended textbooks for you

Database System Concepts

Computer Science

ISBN:

9780078022159

Author:

Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:

McGraw-Hill Education

Starting Out with Python (4th Edition)

Computer Science

ISBN:

9780134444321

Author:

Tony Gaddis

Publisher:

PEARSON

Digital Fundamentals (11th Edition)

Computer Science

ISBN:

9780132737968

Author:

Thomas L. Floyd

Publisher:

PEARSON

Database System Concepts

Computer Science

ISBN:

9780078022159

Author:

Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:

McGraw-Hill Education

Starting Out with Python (4th Edition)

Computer Science

ISBN:

9780134444321

Author:

Tony Gaddis

Publisher:

PEARSON

Digital Fundamentals (11th Edition)

Computer Science

ISBN:

9780132737968

Author:

Thomas L. Floyd

Publisher:

PEARSON

C How to Program (8th Edition)

Computer Science

ISBN:

9780133976892

Author:

Paul J. Deitel, Harvey Deitel

Publisher:

PEARSON

Database Systems: Design, Implementation, & Manag…

Computer Science

ISBN:

9781337627900

Author:

Carlos Coronel, Steven Morris

Publisher:

Cengage Learning

Programmable Logic Controllers

Computer Science

ISBN:

9780073373843

Author:

Frank D. Petruzella

Publisher:

McGraw-Hill Education

SEE MORE TEXTBOOKS

.look at code below then fill the blanks ;int a = 5, b = 2, C = 6, d = 4 if (!b) %3D "cout << "A\n else ;"cout << "B\n if (a == b || c > d) :"cout << "C\n else "cout << "D\n : the output is and