.82 If Y is a continuous random variable and m is the median of the distribution, then m is such that P(Ym) = P(Y ≥ m) = 1/2. If Y₁, Y₂...., Y are independent, exponentially dis- tributed random variables with mean ♬ and median m, Example 6.17 implies that Y() = max(Y₁, Y₂, ..., Y) does not have an exponential distribution. Use the general form of Fy) (y) to show that P(Y) > m) = 1-(.5)".

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6.82 If Y is a continuous random variable and m is the median of the distribution, then m is such
that P(Y ≤m) = P(Y ≥ m) = 1/2. If Y₁, Y₂, ..., Y, are independent, exponentially dis-
tributed random variables with mean ß and median m, Example 6.17 implies that Y(n) =
max (Y₁, Y₂, ..., Yn) does not have an exponential distribution. Use the general form of Fy) (y)
to show that P(Y(n) > m) = 1- (.5)".
Transcribed Image Text:6.82 If Y is a continuous random variable and m is the median of the distribution, then m is such that P(Y ≤m) = P(Y ≥ m) = 1/2. If Y₁, Y₂, ..., Y, are independent, exponentially dis- tributed random variables with mean ß and median m, Example 6.17 implies that Y(n) = max (Y₁, Y₂, ..., Yn) does not have an exponential distribution. Use the general form of Fy) (y) to show that P(Y(n) > m) = 1- (.5)".
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