.65 m² c. 11, 126.15 m² b. 11, 152 d. 11, 156.20 m² SITUATION 11: A closed traverse has the following data: 39. Find the Course 1 - 2 2 - 3 3- 4 4 5 5 1 - Bearing N 9.27 E S 88.43 E N 86.78E S 5.3E S 72.07 W a 29.67 m c. 38.42 m Distance (m) 58.7 m 27.3 m length of the course 3 - 4. 35.0 m b. 36.98 m d. 35.2 m 40. Compute the length of the course 5 - 1. a. 90.30 m 81.14 m b. 78.96 m d. 63.62 m

.65 m² c. 11, 126.15 m² b. 11, 152 d. 11, 156.20 m² SITUATION 11: A closed traverse has the following data: 39. Find the Course 1 - 2 2 - 3 3- 4 4 5 5 1 - Bearing N 9.27 E S 88.43 E N 86.78E S 5.3E S 72.07 W a 29.67 m c. 38.42 m Distance (m) 58.7 m 27.3 m length of the course 3 - 4. 35.0 m b. 36.98 m d. 35.2 m 40. Compute the length of the course 5 - 1. a. 90.30 m 81.14 m b. 78.96 m d. 63.62 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

To get the topography of a given area, a transit was set up at point A and sighted points B and C. The distance of points B and C from A are 200 m and 60 m, respectively. The stadia intervals were determined to be the ff: Stadia Interval Rod at B 2.001 m Rod at C 0.600 m 1. Compute the stadia interval factor. а. 99.93 b. 89.23 с. 94.12 d. 100.01 2. An additional point D was sighted with a stadia interval of 2.12 m. The vertical angle observed is 4°22'. If the elevation of the point where the instrument was set up is 100 m, compute the elevation of point D if the stadia constant is 0.30 m. а. 176.22 m b. 125.23 m c. 151.23 m d. 116.11 m 3. Compute the horizontal distance from the point where the instrument was set up to point D. a. 284.11 m b. 119.73 m с. 182.33 m d. 210.92 m
this is not a graded question and please base your answer on the given choices thank you
A closed traverse has the following data: LINE / LENGTH (m) / Bearing AB / 126.00 m / N 35° E BC / 233.00 m/ S 10° E CA / 170.00 m/ N 41° W 1. || Find the departure disclosure of the traverse. A. 1.201 m B. 2.423 m C. 1.006 m D. 2.321 m 2. Find the latitude disclosure. A. 1.267 m B. 1.889 m C. 2.054 m D. 1.560 m
Co-ordinates of two points Pand Q are given below. A third point Ris so selected that bearings of PR and RQ are 25° 33' and 43°34' respectively. Find the lengths of PR and RQ. Point Northing 135 m 1200 m P Q Easting 150 m 1500 m
567 24'E 8. Given the following sketch and tabulated data for a closed traverse in which the length of DE and the bearing of EF have not been observed in the field. 852.18 m el 3.0E.SON TA 492.98 m 3..80.90 845.85 m N55 27 W 661.26 m Closing Line Unknown Bearing 1210.50 m Unknown Length $12°17″E
LINE DISTANCE(m) AZIMUTH AB 647.25 306.92 deg. BC 203.03 354.32 deg. CD 720.35 195.53 deg. DE 610.24 104.59 deg. EA 275.13 26.16 deg. Given the obtain data from Traversing. Determine the total area of the closed traverse in Acre.
A wide river that is connected to the proposed Kaliwa Dam was measured using a reciprocal leveling and the foresights and backsights were taken and tabulated below. If the elevation of M is 5GB.7962 meters, compute the elevation of point N. Instrument set-up near M Instrument set-up near N STA BS FS STA BS FS M 3.3523 N 2.7C54 M 3.5B58 N 2.6E54 M 3.4891 N 2.5514 M 3.3D19 2.4587 N 2.6E52 M 3.1432 N 2.5429 M 3.2G21 N 2.6G65 M 3.3333 N 2.7754 M 3.4F11 N 2.5E45 M 3.1423 N 2.6551 M 3.2244
18.A traverse has the following data: LINE LENGTH BEARING 20 33.48 N 73°23' E 01 8.11 S 39°30 E 12 39.42 S 43°40' W N 39°50' W N 17°33' W 21 7.08 12 22.02 Use compass rule in adjusting the closed traverse and compute for the Linear Error of Closure and Relative Error of Closure.
q3
2. Given the following data of a closed traverse. LINE BEARING DISTANCE АВ N 38°29' E 33.00 BC S 54°23' E 31.55 CD S009' W 34.20 DE S 77°19' W 26.39 EA a. Compute the bearing of line EA. b. Solve for the distance of line EA. c. Compute the area of the traverse using DPD Method.
Determine the area of traverse using Double Parallel Distance. Ans: 4,028,975 m2