[.6 Let P = be a transition matrix. Which one of the following vectors .4 .7 10 4 10 is the steady-state vector for this transition matrix? Justify your response by demonstrating it is the steady- state vector by a computation that verifies the definition of steady-state vector.

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**Title: Identifying the Steady-State Vector for a Transition Matrix**

Let \( P = \begin{bmatrix} 
0.6 & 0.3 \\ 
0.4 & 0.7 
\end{bmatrix} \) be a transition matrix. Which one of the following vectors

\[ q = \begin{bmatrix} 
\frac{3}{7} \\ 
\frac{4}{7} 
\end{bmatrix} \]

\[ q = \begin{bmatrix} 
\frac{3}{4} \\ 
\frac{1}{4} 
\end{bmatrix} \]

\[ q = \begin{bmatrix} 
\frac{3}{4} \\ 
1 
\end{bmatrix} \]

\[ q = \begin{bmatrix} 
\frac{6}{10} \\ 
\frac{4}{10} 
\end{bmatrix} \]

is the steady-state vector for this transition matrix? Justify your response by demonstrating it is the steady-state vector by a computation that verifies the definition of a steady-state vector.

**Instructions for Verification:**

To verify which vector \( q \) is the steady-state vector, perform the following computation:

1. Multiply the transition matrix \( P \) by each vector \( q \).
2. Check if \( Pq = q \). If the equation holds true, then \( q \) is the steady-state vector for the transition matrix \( P \).

**Definition of Steady-State Vector:**
A vector \( q \) is a steady-state vector for a transition matrix \( P \) if \( Pq = q \). This means that applying the transition matrix to the vector doesn’t change the vector, indicating that it has reached a stable state.

**Note:**
The steady-state vector, also known as the stationary distribution, represents a state where probabilities remain constant upon subsequent applications of the transition probabilities represented by the matrix \( P \). 

This exercise demonstrates an important concept in Markov Chains and the convergence behavior of systems described by transition matrices.
Transcribed Image Text:**Title: Identifying the Steady-State Vector for a Transition Matrix** Let \( P = \begin{bmatrix} 0.6 & 0.3 \\ 0.4 & 0.7 \end{bmatrix} \) be a transition matrix. Which one of the following vectors \[ q = \begin{bmatrix} \frac{3}{7} \\ \frac{4}{7} \end{bmatrix} \] \[ q = \begin{bmatrix} \frac{3}{4} \\ \frac{1}{4} \end{bmatrix} \] \[ q = \begin{bmatrix} \frac{3}{4} \\ 1 \end{bmatrix} \] \[ q = \begin{bmatrix} \frac{6}{10} \\ \frac{4}{10} \end{bmatrix} \] is the steady-state vector for this transition matrix? Justify your response by demonstrating it is the steady-state vector by a computation that verifies the definition of a steady-state vector. **Instructions for Verification:** To verify which vector \( q \) is the steady-state vector, perform the following computation: 1. Multiply the transition matrix \( P \) by each vector \( q \). 2. Check if \( Pq = q \). If the equation holds true, then \( q \) is the steady-state vector for the transition matrix \( P \). **Definition of Steady-State Vector:** A vector \( q \) is a steady-state vector for a transition matrix \( P \) if \( Pq = q \). This means that applying the transition matrix to the vector doesn’t change the vector, indicating that it has reached a stable state. **Note:** The steady-state vector, also known as the stationary distribution, represents a state where probabilities remain constant upon subsequent applications of the transition probabilities represented by the matrix \( P \). This exercise demonstrates an important concept in Markov Chains and the convergence behavior of systems described by transition matrices.
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