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.. Consider the 1-periodic Fourier series expansion ao 9+2 {an cos(2 nnx) + bn sin(2 nmx)} of the function f(x) = ‹ 2 n=1 To which value does it converge at x = 5/2? (A) 0 (B) 1 (C) 1/2 (D) 3 Solution. Since S(r) is 1-periodic, S(5/2) = S(1/2) = [4x², 0

.. Consider the 1-periodic Fourier series expansion ao 9+2 {an cos(2 nnx) + bn sin(2 nmx)} of the function f(x) = ‹ 2 n=1 To which value does it converge at x = 5/2? (A) 0 (B) 1 (C) 1/2 (D) 3 Solution. Since S(r) is 1-periodic, S(5/2) = S(1/2) = [4x², 0

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please explain the highlighted part. Why is because it's 1-periodic, S(1/2) is equal to S(5/2). Please explain how the question would change if it were 2-periodic instead. Thx 

3. Consider the 1-periodic Fourier series expansion +도 + {an cos(2nㅠr) + bn sin(2nx)} of the function f(x) = 2 n=1 To which value does it converge at x = 5/2? (A) 0 (B) 1 (C) 1/2 Solution. Since S(r) is 1-periodic, S(5/2) = S(1/2) [4x2, 0≤x< 호 11/x, 흐드æ<1. f(1/2+) + f(1/2-) 2+1 2 2 (D)3 → (E) 3/2 + f(xt) + f(x)=f(ttf(호) = 2 2 = 2+1 = 3 쓸 2 3-2 2 1 t 초 Q 2 24(월)2 -IN + 2 1 = 1 0드리드를 2 호드 XC1 2
Transcribed Image Text:3. Consider the 1-periodic Fourier series expansion +도 + {an cos(2nㅠr) + bn sin(2nx)} of the function f(x) = 2 n=1 To which value does it converge at x = 5/2? (A) 0 (B) 1 (C) 1/2 Solution. Since S(r) is 1-periodic, S(5/2) = S(1/2) [4x2, 0≤x< 호 11/x, 흐드æ<1. f(1/2+) + f(1/2-) 2+1 2 2 (D)3 → (E) 3/2 + f(xt) + f(x)=f(ttf(호) = 2 2 = 2+1 = 3 쓸 2 3-2 2 1 t 초 Q 2 24(월)2 -IN + 2 1 = 1 0드리드를 2 호드 XC1 2
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