. With a = .05, how are the boundaries for the critical region determined in a one-tailed distribution? a. Boundaries are drawn so there are 2.5% (.025) of scores in one tail of the distribution. b. Boundaries are drawn so there are 5% (.05) of scores in one tail of the distribution. c. Boundaries are drawn so there are 10% (.10) of scores in one tail of the distribution. d. Boundaries are drawn so there are 5% (.05) of scores in the center of the distribution.

Q: 4. If we randomly pull a number from B, what is the probability that it is also an element of A? P…

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Q: 5.78+9.1

A: We have given that,  5.78+9.1 We will find the addition of the given values?

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A: To find 63.52x4.7

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A: The given diagram is

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A: Consider the given expression as 411×59. 411×59=4×511×9=2099

Q: 62 a,b,c

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Q: 74.1 6.

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Q: 12 wikon 3.

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Q: 40 10

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Q: 10| 5 10 10 -5 -5

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Q: 2 10 8 1 0 07 -9 -8 - 5 0 1 0 4 9 0 1

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Q: 6 9.06

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Q: —5л 6.

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A: We use  Sin(a+b) = sin(a)cos(b) + cos(a) sin(b)  Pythagoras theorem (Hypotenuse)2 =…