1. Using the measured circumference (c= 21.3 cm) of the glass ornament, calculate the radius in cm. Formula for circumference of a sphere= 2(3.14) r. 2. Using the radius from above, calculate the surface area (cm^2) of the ornament. (Surface area= 4(3.14)r^2)3. Calculate the mass of the silver that is in the glass ornament. (Final mass-Initial mass)Initial mass- 14.43Final mass- 14.534. The density of silver is 10.5 g/cm^3. What is the volume of the silver metal lining the inside of the glass ornament?5. Assume that the volume of silver in the ornament can be approximated by the following equation: Volume= Surface area x thickness. Calculate the approximate thickness of the silver lining in cm and convert the answer to picometers (1x10^12 pm= 1m).6. If the radius of a silver atom is 160 pm, what is the diameter of a silver atom. How many silver atoms thick is the lining? **Silver Holiday Ornaments****Questions**1. Using the measured circumference of the glass ornament, calculate the radius (in cm). The formula for the circumference of a sphere is \(2\pi r\). *Circumference = 21.3 cm*2. Using the radius from above, calculate the surface area (\(cm^2\)) of the ornament. *(Surface area = \(4\pi r^2\))*3. Calculate the mass of the silver that is in the glass ornament. (Subtract the mass of the ball before and after the silver is added.) *Initial mass = 14.43 g* *Final mass = 14.53 g*4. The density of silver is \(10.5 \, \text{g/cm}^3\). What is the volume of silver metal lining the inside of the glass ornament?5. Assume that the volume of silver in the ornament can be approximated by the following equation: Volume = Surface area × thickness. Calculate the approximate thickness of the silver lining in centimeters, and convert the answer to picometers \((1 \times 10^{12} \, \text{pm} = 1 \, \text{m})\).6. If the radius of a silver atom is 160 pm, what is the diameter of a silver atom? How many silver atoms thick is the lining?

We have to find How many silver atoms thick is the lining? Given radius of a silver atom is 160 pm

Answered: . Using the measured circumference (c=…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

1. Using the measured circumference (c= 21.3 cm) of the glass ornament, calculate the radius in cm. Formula for circumference of a sphere= 2(3.14) r. 2. Using the radius from above, calculate the surface area (cm^2) of the ornament. (Surface area= 4(3.14)r^2) 3. Calculate the mass of the silver that is in the glass ornament. (Final mass-Initial mass) Initial mass- 14.43 Final mass- 14.53 4. The density of silver is 10.5 g/cm^3. What is the volume of the silver metal lining the inside of the glass ornament? 5. Assume that the volume of silver in the ornament can be approximated by the following equation: Volume= Surface area x thickness. Calculate the approximate thickness of the silver lining in cm and convert the answer to picometers (1x10^12 pm= 1m). 6. If the radius of a silver atom is 160 pm, what is the diameter of a silver atom. How many silver atoms thick is the lining?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions