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. There is a very hot (600 °C) stream of oil exiting a reactor at 100 3. 1 kg/min that must be immediately quenched to 95 °C. One way to do this is to rapidly mix the oil with water available at 75 °F in a static mixer. The oil will cool, and the water will warm. After they are thermally equilibrated, the two can be separated by a simple decantation process (oil and water don't mix). Given that the heat capacity of oil is 2.56 kJ/kg-K, and that the heat capacity of water is 4.20 kJ/kg-K, what water flow is required? Oil at 95 °C 100 kg/min oil at 600 °C Mixer Mixture at 95 °C Water at 75 °F Water at 95 °C

. There is a very hot (600 °C) stream of oil exiting a reactor at 100 3. 1 kg/min that must be immediately quenched to 95 °C. One way to do this is to rapidly mix the oil with water available at 75 °F in a static mixer. The oil will cool, and the water will warm. After they are thermally equilibrated, the two can be separated by a simple decantation process (oil and water don't mix). Given that the heat capacity of oil is 2.56 kJ/kg-K, and that the heat capacity of water is 4.20 kJ/kg-K, what water flow is required? Oil at 95 °C 100 kg/min oil at 600 °C Mixer Mixture at 95 °C Water at 75 °F Water at 95 °C

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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3. г J. There is a very hot (600 °C) stream of oil exiting a reactor at 100 kg/min that must be immediately quenched to 95 °C. One way to do this is to rapidly mix the oil with water available at 75 °F in a static mixer. The oil will cool, and the water will warm. After they are thermally equilibrated, the two can be separated by a simple decantation process (oil and water don't mix). Given that the heat capacity of oil is 2.56 kJ/kg-K, and that the heat capacity of water is 4.20 kJ/kg-K, what water flow is required? Oil at 95 °C 100 kg/min oil at 600 °C Mixer Mixture at 95 °C Water at 75 °F Water at 95 °C
Transcribed Image Text:3. г J. There is a very hot (600 °C) stream of oil exiting a reactor at 100 kg/min that must be immediately quenched to 95 °C. One way to do this is to rapidly mix the oil with water available at 75 °F in a static mixer. The oil will cool, and the water will warm. After they are thermally equilibrated, the two can be separated by a simple decantation process (oil and water don't mix). Given that the heat capacity of oil is 2.56 kJ/kg-K, and that the heat capacity of water is 4.20 kJ/kg-K, what water flow is required? Oil at 95 °C 100 kg/min oil at 600 °C Mixer Mixture at 95 °C Water at 75 °F Water at 95 °C
Expert Solution
Step 1

Initial oil temperature, Toil(1) = 600°C = 873 K

Initial water temperature, Twater(1) = 75°F = 297.039 K

Final mixture temperature, T2 = 95°C = 368 K

Flow rate of oil, moil = 100 kg/min

Specific heat capacity of oil, Coil = 2.56 kJ/kg.K

Specific heat capacity of water, Cwater = 4.20 kJ/kg.K

The schematic process diagram for the given process is:

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