*. The value of A within a solid nonmagnetic conductor of radius a carrying a total current I in the a- direction may be found easily. Using the known value of H or B for p< a, then (46) may be solved for A. Select A = (uol In 5)/2n at p= a (to correspond with an example in the next section) and find A at p=: (a) 0; (b) 0.25a, (c) 0.75a, (d) a. Ans. 0.422 u Wb/m; 0.416 u Wb/m; 0.366 µ Wb/m; 0.322 µ Wb/m

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°. The value of A within a solid nonmagnetic conductor of radius a carrying a total
current I in the a: direction may be found easily. Using the known value of H or B for
p< a, then (46) may be solved for A. Select A = (uol In 5)/2n at p= a (to correspond
with an example in the next section) and find A at p=: (a) 0; (b) 0.25a; (c) 0.75a, (d) a.
Ans. 0.422 μ Wb/m; 0.416 μ Wb/m; 0.366 μ Wb/m: 0.322 μ Wb/m
Transcribed Image Text:°. The value of A within a solid nonmagnetic conductor of radius a carrying a total current I in the a: direction may be found easily. Using the known value of H or B for p< a, then (46) may be solved for A. Select A = (uol In 5)/2n at p= a (to correspond with an example in the next section) and find A at p=: (a) 0; (b) 0.25a; (c) 0.75a, (d) a. Ans. 0.422 μ Wb/m; 0.416 μ Wb/m; 0.366 μ Wb/m: 0.322 μ Wb/m
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