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. The two switches in the circuit shown below are synchronized. The switches have been closed for a long time before opening at t = 0. a) How many microseconds after the switches are open is the energy dissipated in the 60 kn resistor 25% of the initial energy stored in the 200 mH inductor? b) At the time calculated in part (a), what percentage of the total energy stored in the inductor has been dissipated? t = 0, 120 mA 40 kn ΚΩ t=0 200 mH 20 ΚΩ 60 ΚΩ • 30 ΚΩ

. The two switches in the circuit shown below are synchronized. The switches have been closed for a long time before opening at t = 0. a) How many microseconds after the switches are open is the energy dissipated in the 60 kn resistor 25% of the initial energy stored in the 200 mH inductor? b) At the time calculated in part (a), what percentage of the total energy stored in the inductor has been dissipated? t = 0, 120 mA 40 kn ΚΩ t=0 200 mH 20 ΚΩ 60 ΚΩ • 30 ΚΩ

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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. The two switches in the circuit shown below are synchronized. The switches have been closed for a long time before opening at t = 0. a) How many microseconds after the switches are open is the energy dissipated in the 60 k n resistor 25% of the initial energy stored in the 200 mH inductor? b) At the time calculated in part (a), what percentage of the total energy stored in the inductor has been dissipated? t = 0. 120 mA 40 kn ΚΩ t = 0 200 mH Σ 20 ΚΩ 60 ΚΩ • 30 ΚΩ
Transcribed Image Text:. The two switches in the circuit shown below are synchronized. The switches have been closed for a long time before opening at t = 0. a) How many microseconds after the switches are open is the energy dissipated in the 60 k n resistor 25% of the initial energy stored in the 200 mH inductor? b) At the time calculated in part (a), what percentage of the total energy stored in the inductor has been dissipated? t = 0. 120 mA 40 kn ΚΩ t = 0 200 mH Σ 20 ΚΩ 60 ΚΩ • 30 ΚΩ
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