. The Newton-Raphson method formula for finding the square root of a real number R from the equation, x²-R = 0 is, c. X+1 =(x +) (3x - Xi+1 = 2 a. %3D b. 3x Xi+1 d. Xi+1 =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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1. The Newton-Raphson method formula for finding the square root of a real number R from the equation,
x²-R = 0 is,
a.
Xi+1
+
2
c. X1+1 =
b.
3x
d. X+1=(3x, -5
Xi+1
2. To ensure that the following system of equation,
= -18
3X, + 20X, - X3 =
20X, +X2 – 2X3 = 17
2X1 – 3X, + 20X3 = 25
is converge using Jacob's method, one can rewrite as:
3
20
1.
-1
-18
2
-3
20
25
a. 20
2
-2 = 17
-18
-2 =
17
с. 20
-3
20
25
3.
20
-1
20
1
-2
17
b.
3
20
-1 = -18
-3
20
25
d. None of them.
3. Given the following table and by using linear interpolation, y (5.3) will be:
5.5
y
1.609
1.704
1.791
а. 1.666
C. 1.776
b. 1.566
d. none of them
2.2
4. The value of xe dx by using one - segment trapezoidal rule is most nearly,
a. 11.672
с. 20.099
b. 11.807
d. 24.119
Transcribed Image Text:1. The Newton-Raphson method formula for finding the square root of a real number R from the equation, x²-R = 0 is, a. Xi+1 + 2 c. X1+1 = b. 3x d. X+1=(3x, -5 Xi+1 2. To ensure that the following system of equation, = -18 3X, + 20X, - X3 = 20X, +X2 – 2X3 = 17 2X1 – 3X, + 20X3 = 25 is converge using Jacob's method, one can rewrite as: 3 20 1. -1 -18 2 -3 20 25 a. 20 2 -2 = 17 -18 -2 = 17 с. 20 -3 20 25 3. 20 -1 20 1 -2 17 b. 3 20 -1 = -18 -3 20 25 d. None of them. 3. Given the following table and by using linear interpolation, y (5.3) will be: 5.5 y 1.609 1.704 1.791 а. 1.666 C. 1.776 b. 1.566 d. none of them 2.2 4. The value of xe dx by using one - segment trapezoidal rule is most nearly, a. 11.672 с. 20.099 b. 11.807 d. 24.119
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