. The crew of the spacecraft conducted research on the collision of an atom. if the hydrogen atom (m = 1.67355 x 10 ^ -27 kg) is moving at the velocity vH = 3.518 x 10 ^ 7 m / s colliding with the nitrogen atom at rest (mN = 2.353 x 10 ^ -26 kg). After the collision, the hydrogen atom is known to be moving with the velocity v'H = 1.353 x 10 ^ 6 m / s at an angle (thaH = 66.74 degrees) relative to the origin of the motion of the hydrogen atom. determine the velocity (magnitude and direction) of the nitrogen atom after the collision and compare the kinetic energy before and the total kineic energy of the atoms after the collision, explaining the meaning of this kinetic energy ratio.
an aerospace is moving away from the earth at a velocity v = 0.6c to carry out a research. when the aircraft is at a distance of d = 5 x 10 ^ 8 km from the earth, a radio signal is sent to the aircraft from observers on earth. Count it
a. The crew of the spacecraft conducted research on the collision of an atom. if the hydrogen atom (m = 1.67355 x 10 ^ -27 kg) is moving at the velocity vH = 3.518 x 10 ^ 7 m / s colliding with the nitrogen atom at rest (mN = 2.353 x 10 ^ -26 kg). After the collision, the hydrogen atom is known to be moving with the velocity v'H = 1.353 x 10 ^ 6 m / s at an angle (thaH = 66.74 degrees) relative to the origin of the motion of the hydrogen atom. determine the velocity (magnitude and direction) of the nitrogen atom after the collision and compare the kinetic energy before and the total kineic energy of the atoms after the collision, explaining the meaning of this kinetic energy ratio.
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