. Stock received products form 2 suppliers. Supplier A provided 4000pc. of products, Supplier B provided 6000pc. of products. Products are of 2 types: type 1 and type2. In products provided by supplier A there are 20% of type 2 products. IN,n products provided by supplier B there are 10% of type 2 products. We picked up a product from all products and it is of type 1. Find out probability that: a. It is from supplier A b. It is from supplier B

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1. Stock received products form 2 suppliers. Supplier A provided 4000pc.
of products, Supplier B provided 6000pc. of products. Products are of 2
types: type 1 and type2. In products provided by supplier A there are
20% of type 2 products. IN,n products provided by supplier B there are
10% of type 2 products. We picked up a product from all products and
it is of type 1. Find out probability that:
a. It is from supplier A
b. It is from supplier B
Transcribed Image Text:1. Stock received products form 2 suppliers. Supplier A provided 4000pc. of products, Supplier B provided 6000pc. of products. Products are of 2 types: type 1 and type2. In products provided by supplier A there are 20% of type 2 products. IN,n products provided by supplier B there are 10% of type 2 products. We picked up a product from all products and it is of type 1. Find out probability that: a. It is from supplier A b. It is from supplier B
Expert Solution
Step 1

Let us denote: A=supplier AB=supplier BC=type 1D=type 2Given that: n(A)=4000, n(B)=6000.So, P(A)=40004000+6000=0.4, P(B)=60004000+6000=0.6Given that P(D|A)=20%=0.20, so, P(C|A)=1-0.20=0.80P(D|B)=10%=0.10, so, P(C|B)=1-0.10=0.90

Step 2

a) The probability that the product is from supplier A given that it is of type 1 is:P(A|C)=P(A and C)P(C)=P(A and C)P(A and C)+P(B and C)=P(A)P(C|A)P(A)P(C|A)+P(B)P(C|B)=0.4×0.800.4×0.80+0.6×0.90=0.372093023256Answer(a): 0.372093023256

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