. One might need to find solutions of Ax = b for several different b’s, say bị, ., bỵ. In this event, one can augment the matrix A with all the b’s simultaneously, forming the "multi-augmented" matrix [ A | b¡ b2 ·.. bị ]. One can then read off the various solutions from the reduced echelon form of the multi-augmented matrix. Use this method to solve Ax = b; for the given matrices A and vectors b;. 1 0 -1 a. A = 1 -1 bị b2 = | 3 2 2 1 b. A = 2 -1 bị = 1 b2 3 2 1 1 c. A = | 0 1 1 bị = b2 = b3 1 2 1 2.
. One might need to find solutions of Ax = b for several different b’s, say bị, ., bỵ. In this event, one can augment the matrix A with all the b’s simultaneously, forming the "multi-augmented" matrix [ A | b¡ b2 ·.. bị ]. One can then read off the various solutions from the reduced echelon form of the multi-augmented matrix. Use this method to solve Ax = b; for the given matrices A and vectors b;. 1 0 -1 a. A = 1 -1 bị b2 = | 3 2 2 1 b. A = 2 -1 bị = 1 b2 3 2 1 1 c. A = | 0 1 1 bị = b2 = b3 1 2 1 2.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

Transcribed Image Text:а. А —
2
b. A =
12
-9
1
1
16 -13
7. One might need to find solutions of Ax = b for several different b's, say bị, ..., b..
In this event, one can augment the matrix A with all the b's simultaneously, forming
the "multi-augmented" matrix [ A | bị b2 ...
solutions from the reduced echelon form of the multi-augmented matrix. Use this
method to solve Ax = b;
bị J. One can then read off the various
m
for the given matrices A and vectors b;.
1
-1
а. А:
2
1 -1
bị
1
b2
3
-1
2
2
5
2
1
b. А:
2 -1
bị
b2
2
1
1
1
1
с. А -
1
bị =
b2
b3
||
ID3
Expert Solution

Step 1
first we will reduce the multi augmented matrix into reduced echelon form (rref) then find the solution of systems AX=bi
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