. On R2, evaluate the integral JS₂₂ 1 R² (x² + y² + 1)² Notice that this is an improper integral. dx dy lim lim = R→∞T→∞ X Let w = (u, v) = ( ₁² + ₁²² +² + y²) SS₁₂ (2²+2 ² + 1)² 1 R2 R du dv L T 1 -R (x² + y² + 1)² -T (x². evaluate the improper integral dx dy. Notice that beside the limit as u or v goes to infinity, this function is in fact not even defined at (u, v) = (0,0). 1

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