. Let A and B be square n x n matrices. Show that det AB = det BA even though in general, AB ‡ BA. • Prove that if A is invertible, then det (A-¹) = (det A)-¹. .

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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- Let \( A \) and \( B \) be square \( n \times n \) matrices. Show that \(\det(AB) = \det(BA)\) even though in general, \( AB \neq BA \).
- Prove that if \( A \) is invertible, then \(\det(A^{-1}) = (\det A)^{-1}\).
Transcribed Image Text:- Let \( A \) and \( B \) be square \( n \times n \) matrices. Show that \(\det(AB) = \det(BA)\) even though in general, \( AB \neq BA \). - Prove that if \( A \) is invertible, then \(\det(A^{-1}) = (\det A)^{-1}\).
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