. Lead (II) chloride can be produced from the reaction between hydrochloric acid and Lead (11 hydroxide given by the equation below (MM: Pb = 207.2 g/mol, H = 1.008 g/mol, Cl = 35.45 g/mol): HCl(aq) + Pb(OH)2(aq) --> PbCl2(s) + H₂O (1) a. How many grams of PbCl₂ will be produced from 2.602 grams of Pb(OH)2? b. If 0.5 M HCI is used to produce the PbCl2, how many liters of HCI solution is needed to produce 5.00 g of PbCl₂?

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1. Lead (II) chloride can be produced from the reaction between hydrochloric acid and Lead (II)
hydroxide given by the equation below (MM: Pb = 207.2 g/mol, H = 1.008 g/mol, Cl = 35.45
g/mol):
HCl(aq) + Pb(OH)2(aq) --> PbCl2(s) + H₂O(1)
a.
How many grams of PbCl₂ will be produced from 2.602 grams of Pb(OH)2?
b. If 0.5 M HCI is used to produce the PbCl₂, how many liters of HCI solution is needed to
produce 5.00 g of PbCl₂?
almal
Transcribed Image Text:1. Lead (II) chloride can be produced from the reaction between hydrochloric acid and Lead (II) hydroxide given by the equation below (MM: Pb = 207.2 g/mol, H = 1.008 g/mol, Cl = 35.45 g/mol): HCl(aq) + Pb(OH)2(aq) --> PbCl2(s) + H₂O(1) a. How many grams of PbCl₂ will be produced from 2.602 grams of Pb(OH)2? b. If 0.5 M HCI is used to produce the PbCl₂, how many liters of HCI solution is needed to produce 5.00 g of PbCl₂? almal
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