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. In the figure below, calculate the output voltage Vout, and the phase angle with VIN at 150 KHz. VIN = 200 mvp-p for all frequencies C1 = 0.0022 uf www R1 = 1 k Output |

. In the figure below, calculate the output voltage Vout, and the phase angle with VIN at 150 KHz. VIN = 200 mvp-p for all frequencies C1 = 0.0022 uf www R1 = 1 k Output |

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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### Problem Statement Calculate the output voltage \( V_{\text{out}} \) and the phase angle \( \theta \) with \( V_{\text{IN}} \) at 150 kHz. ### Circuit Description - **Input Voltage Source**: \( V_{\text{IN}} = 200 \text{ mV}_{\text{P-P}} \) for all frequencies. - **Capacitor**: \( C1 = 0.0022 \mu\text{F} \) - **Resistor**: \( R1 = 1 \text{ k}\Omega \) - **Output**: Taken across the resistor \( R1 \). ### Diagram Explanation This is a simple RC low-pass filter circuit. The input AC voltage \( V_{\text{IN}} \) passes through a capacitor (\( C1 \)), and the resulting voltage is measured across a resistor (\( R1 \)). The output is taken across the resistor, which is in series with the capacitor. This configuration affects both the amplitude and phase of the output signal relative to the input signal, especially noticeable at higher frequencies.
Transcribed Image Text:### Problem Statement Calculate the output voltage \( V_{\text{out}} \) and the phase angle \( \theta \) with \( V_{\text{IN}} \) at 150 kHz. ### Circuit Description - **Input Voltage Source**: \( V_{\text{IN}} = 200 \text{ mV}_{\text{P-P}} \) for all frequencies. - **Capacitor**: \( C1 = 0.0022 \mu\text{F} \) - **Resistor**: \( R1 = 1 \text{ k}\Omega \) - **Output**: Taken across the resistor \( R1 \). ### Diagram Explanation This is a simple RC low-pass filter circuit. The input AC voltage \( V_{\text{IN}} \) passes through a capacitor (\( C1 \)), and the resulting voltage is measured across a resistor (\( R1 \)). The output is taken across the resistor, which is in series with the capacitor. This configuration affects both the amplitude and phase of the output signal relative to the input signal, especially noticeable at higher frequencies.
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