. Imagine a giant sphere with a radius of 1 AU surrounding the Sun. What is the surface area of this sphere, in square meters? (Hint: The formula for the surface area of a sphere is 4nr².)
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Q: Multiply 1.52 AU by 150 million km: 1.52 x 150,000,000 = 228,000,000 km
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A: Distance, d = 7 pc Original Magnitude, M=-4.7 Need to find the apparent magnitude.
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A: Diameter of our solar systemD= 10 billion km
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A: Given Diameter of Sun D = 865,380 miles Diameter of Saturn d = 72,368 miles Objects and their…
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- Can you answer the question?Imagine that in the future, scientists plan on colonizing planets that orbit other stars. Based on your knowledge of the life cycle of stars, decide which type of star (High mass or Low mass) the planet should orbit that would allow for human life to safely live on that planet for the longest period of time. Explain your answer using examples from the life cycle of each star.What is the apparent magnitude of the sun as seen from Saturn about 10 AU away? Appear to magnitude of Saturn =
- I need help with this question! There is only one part to it!1) How massive would Earth had been if it had accreted hydrogen compounds in addition to the sme properties listed in table 7.1? (Assume the same properties of the ingredients as listed in the table) 2) Now imagine that Earth had been able to capture hydrogen and helium gas in the same proportions as listed in the table. How massive would it have been?Next you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law. Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU (2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5) Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU. A) Calculate a in AU. B) Convert your measurement of the moon's orbital period from days to years. C) By Newton's form of Kepler's third law, calculate the mass of the planet. D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.
- Read this main idea: The sun is the center of our solar system. Choose three details that go with the main idea. The sun's gravity holds the planets in place. It provides them with heat and light. The largest stars, called supergiants, are 1,500 times bigger than our sun. It takes Earth 365 days to orbit the sun. Jupiter takes 12 years! Our sun is not the largest or hottest star. It is a medium sized yellow star. Radio telescopes use radio waves to show stars in great detail. Astronomers long ago and today use star charts to map star locations. All of the planets in our solar system revolve around one star-our sun. Stars can be blue, white, yellow, or red. Blue stars are the hottest. A reflector telescope bounces star light through mirrors.3You are given the following data from observations of an exoplanet: Using Kepler’s Third Law (r3 = MT2 where M is the mass of the central star) find the orbital radius in astronomical units of this planet. M = 1.5 times the mass of the sun. Remember to convert days to years using 365.25 as the length of a year in days. What is the semimajor axis of this planet in AU? - Knowing the orbital radius in both kn and AU, use the value in km to find the circumference of the orbit, then convert that to meters. (Assume the orbit is a perfect circle). - Knowing the orbital circumference and the period in days, convert the days to seconds (multiply by 86,400) and find the orbital velocity in m/s - With that orbital velocity, the radius of the orbit in meters, find the centripetal acceleration of our exoplanet - Knowing the acceleration that our planet experiences, calculate the force that the host star exerts on the planet - Knowing the force on the planet, the orbital radius, and the mass of the…
- The speed of the solar wind is approximately 400 km/s. How many days does the solar wind take to travel from the Sun to Jupiter? (Notes: 1 AU = 1.5 ✕ 108 km;1 day = 86,400 s.)The Sun has a radius of 6.955×105 km and a mass of 1.989×1030 kg. What is the density of the Sun? Answer: ____ kg/m3 How does this compare to the density of Earth (5500 kg/m3)? Answer: ____ times the density of EarthVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. ote: 1 pc = 2.1 x 10° AU). times fainter What would its apparent magnitude be? Need Help? Read It