. Hungerford defines exponentiation in Zn on p. 36. Note that, from that definition, together with the definition of multiplication in Zn (p. 32), it follows that [a]* = [a*] in Zn, for all a E Z and k E Z>1. Compute the following. [52000] in Z4. [42001] in Z5. [39003] in Z7. (a) (b)
. Hungerford defines exponentiation in Zn on p. 36. Note that, from that definition, together with the definition of multiplication in Zn (p. 32), it follows that [a]* = [a*] in Zn, for all a E Z and k E Z>1. Compute the following. [52000] in Z4. [42001] in Z5. [39003] in Z7. (a) (b)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Hungerford defines exponentiation in Zn on p. 36. Note that, from that definition,
together with the definition of multiplication in Zn (p. 32), it follows that [a]k = [a*]
in Zn, for all a E Z and k E Z>1. Compute the following.
[52000] in Z4.
[42001] in Zg.
[39008] in Z7.
(a)
(b)
(c)
Hint: Again, if you're using a calculator or computer to do these problems, you're
missing the point. With a little theory, you can solve these problems using computa-
tions that you easily do in your head!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87bd9bd0-40fd-4172-a50a-abb52eb6a8c1%2Fe8b066b0-9619-4f1f-a3cf-f40e2d6ff442%2Fpd00by_processed.png&w=3840&q=75)
Transcribed Image Text:Hungerford defines exponentiation in Zn on p. 36. Note that, from that definition,
together with the definition of multiplication in Zn (p. 32), it follows that [a]k = [a*]
in Zn, for all a E Z and k E Z>1. Compute the following.
[52000] in Z4.
[42001] in Zg.
[39008] in Z7.
(a)
(b)
(c)
Hint: Again, if you're using a calculator or computer to do these problems, you're
missing the point. With a little theory, you can solve these problems using computa-
tions that you easily do in your head!
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