. Find the value of (2) for a solution (x) to the initial value problem: y” + 4y' + 4y = 2x + 6; y(0) = 1, y'(0) = 1/1. e¹+3 -2e-4+1 2 5 773
. Find the value of (2) for a solution (x) to the initial value problem: y” + 4y' + 4y = 2x + 6; y(0) = 1, y'(0) = 1/1. e¹+3 -2e-4+1 2 5 773
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![1. Choose a solution to the differential equation y" - y = x²eª + 5.
eª (₹¹x² + ¼x − 1 ) + 2e¯ª -
-
ex²-e-+6
x
ex (3x³ - 2x²-x) -2e - 5
e
€¯ª ( ²x³ — — x² + x + 3) - 2e² +5
e²(³x²+x-1)+2e-5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07617c3b-9260-44d5-81a8-49b7273066f7%2F5b6fa411-f4dc-47a6-80a0-6041a80902ba%2Ftenmi2d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. Choose a solution to the differential equation y" - y = x²eª + 5.
eª (₹¹x² + ¼x − 1 ) + 2e¯ª -
-
ex²-e-+6
x
ex (3x³ - 2x²-x) -2e - 5
e
€¯ª ( ²x³ — — x² + x + 3) - 2e² +5
e²(³x²+x-1)+2e-5
![2. Find the value of (2) for a solution (x) to the initial value problem:
y" + 4y + 4y = 2x + 6; y(0) = 1, y'(0) = 1/2.
e
2
-2e
UT
5
- انت
-4
3
+3
+1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07617c3b-9260-44d5-81a8-49b7273066f7%2F5b6fa411-f4dc-47a6-80a0-6041a80902ba%2Fiswvmqk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Find the value of (2) for a solution (x) to the initial value problem:
y" + 4y + 4y = 2x + 6; y(0) = 1, y'(0) = 1/2.
e
2
-2e
UT
5
- انت
-4
3
+3
+1
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