Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rbhas charge -Q. The electric field E at a radial distance r from the central axis is given by the function:E = ae-r/ao + B/r + bowhere alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance.First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by:Vab =EdrEdrCalculating the antiderivative or indefinite integral,Vab = (-aager/a0 + B+ boBy definition, the capacitance C is related to the charge and potential difference by:C =Evaluating with the upper and lower limits of integration for Vab, then simplifying:C= Q/((e-rb/ao - eTa/ao) + ß In() + bo ())

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. Find an expression for its capacitance.

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

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Question

Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb
has charge -Q. The electric field E at a radial distance r from the central axis is given by the function:
E = ae-r/ao + B/r + bo
where alpha (a), beta (B), ao and bo are constants. Find an expression for its capacitance.
First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by:
Vab =
Edr
Edr
Calculating the antiderivative or indefinite integral,
Vab = (-aager/a0 + B
+ bo
By definition, the capacitance C is related to the charge and potential difference by:
C =
Evaluating with the upper and lower limits of integration for Vab, then simplifying:
C= Q/(
(e-rb/ao - eTa/ao) + ß In(
) + bo (
))

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