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. During a science experiment, a chemist boils a liquid then sets it on the lab table and records the temperature as it cools. The graph shows y, the temperature in degress centigrade, and x is the number of minutes after the liquid is set on the table. Liquid Temperature Temperature (°C) y 120 1004 80 60 40 20 0 5 10 15 20 25 30 35 40 45 Time (minutes) Which equation is the best model for this data? Ay=100(0.75)* By= (0.75) +100 Oy=80 (0.75)' +20 5 y=20 (0.75)' +80 X

. During a science experiment, a chemist boils a liquid then sets it on the lab table and records the temperature as it cools. The graph shows y, the temperature in degress centigrade, and x is the number of minutes after the liquid is set on the table. Liquid Temperature Temperature (°C) y 120 1004 80 60 40 20 0 5 10 15 20 25 30 35 40 45 Time (minutes) Which equation is the best model for this data? Ay=100(0.75)* By= (0.75) +100 Oy=80 (0.75)' +20 5 y=20 (0.75)' +80 X

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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2.1 2. During a science experiment, a chemist boils a liquid then sets it on the lab table and records the temperature as it cools. The graph shows y, the temperature in degress centigrade, and x is the number of minutes after the liquid is set on the table. Liquid Temperature Temperature (°C) y 120 100 80 60 40 20 X 0 5 10 15 20 25 30 35 40 45 Time (minutes) Which equation is the best model for this data? y=100(0.75)* By=(0.75)* + 100 Oy=80(0.75) +20 Dy=20(0.75) +80 1
Transcribed Image Text:2.1 2. During a science experiment, a chemist boils a liquid then sets it on the lab table and records the temperature as it cools. The graph shows y, the temperature in degress centigrade, and x is the number of minutes after the liquid is set on the table. Liquid Temperature Temperature (°C) y 120 100 80 60 40 20 X 0 5 10 15 20 25 30 35 40 45 Time (minutes) Which equation is the best model for this data? y=100(0.75)* By=(0.75)* + 100 Oy=80(0.75) +20 Dy=20(0.75) +80 1
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